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Svetach [21]
3 years ago
9

Question 2.4 please. If 250ml of 1.5M Ba(OH)2 solution mixes with 250ml of 2.0M of HCl solution, calculate the increase in tempe

rature given that the two solutions have the same initial temperatures.

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
5 0
Do you still need help?

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which atom has a change in oxidation number of -3 in the following redox reaction K2Cr2O7 + H2O +S --> KOH + Cr2O3 +SO2
yaroslaw [1]
You have to calculate the oxidation estates of the atoms in each compound.

I will start with K2Cr2O7 because I believe that Cr is the best candidate to reduce its oxidation number in 3 units.

In K2Cr2O7:

- K has oxidation state of 1+, then K2 has a charge of 2* (1+) = 2+.

- O has oxidation state of 2*, then O7 has a charge of 7* (2-) = 14-.

That makes that Cr2 has charge of 14 - 2 = +12, so each Cr has +12/2 = +6 oxidation state.

In Cr2O3:

- O has oxidation state of 2-, then O3 has charge 3 * (2-) = - 6

- Then, Cr2 has charge 6+, and each Cr has charge 6+ / 2 = 3+.

So, we have seen that Cr reduced its oxidation state in 3 units, from 6+ to 3+.

Answer: Cr has a change in oxidation number of - 3.
6 0
3 years ago
(01.01 LC)
Usimov [2.4K]

The answer would be "false" or the second option. A opinion is what you think on a certain subject and science is full of facts and opinions of other scientist which would mean your using someone else for your opinion just remember opinions is what you think about a subject and you can't use science for your opinion.

Hope this helps!

7 0
3 years ago
Read 2 more answers
Compounds X and Y are both C6H13Cl compounds formed in the radical chlorination of 3-methylpentane. Both X and Y undergo base-pr
zubka84 [21]

Answer:

Y is a 3-chloro-3-methylpentane.

The structure is shown in the figure attached.

Explanation:

The radical chlorination of 3-methylpentane can lead to a tertiary substituted carbon (Y) and to a secondary one (X).

The E2 elimination mechanism, as shown in the figure, will happen with a simulyaneous attack from the base and elimination of the chlorine. This means that primary and secondary substracts undergo the E2 mechanism faster than tertiary substracts.

6 0
2 years ago
you are given an unknown gaseous binary compound. when 10.0g of the compound isburned in excess oxygen, 16.3g of water is produc
Flauer [41]
Since the compound has 1.38 time that of oxygen gas at the same conditions of temperature and pressure, we have the relationship:
MW/MWoxygen = 1.38
MW = 44.16

Since there is water formed during the reaction, the formula of the compound must be:
XaHb
where a and b are the coefficients of each element.

If the compound reactions with oxygen forming water and an oxide of the element X, the combustion reaction must be:
XaHb + ((2a + (b/2))/2) O2 = a (XO2) + (b/2)(H2O)
Using dimensional analysis:
10 (1/44.16) (b/2 / 1) (18) = 16.3
Solving for b:
b = 8

The compound now is XaH8. Most probably, the compound is C3H8 since it has a molecular formula of 44 and it reacts with O2 to form water and CO2.
5 0
3 years ago
To find the atomic mass of a particular atom you need to know
AveGali [126]
The answer is (C) as the definitions states that atomic mass is the number of protons and neutrons.
Hope this helps :).
6 0
2 years ago
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