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3 years ago

What is the equation for momentum

Physics

2 answers:

Marina CMI [18]3 years ago

5 0

Answer:

p=mv

Explanation:

i looked it up.

s2008m [1.1K]3 years ago

4 0

Answer:

p=mv I think I hope:):)

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Jennifer regularly instructs her students to avoid believing age-old theories about the differences between men and women. “As i

Agata [3.3K]

The best answer would be a "non-directional hypothesis"

6 0

3 years ago

Read 2 more answers

The large blade of a helicopter is rotating in a horizontal circle. The length of the blade is 7.17 m, measured from its tip to

gayaneshka [121]

Answer:

1.789

Explanation:

let the tangential velocity at the tip of the blade (7.17m from center) be V₁ and the tangential velocity at 4.01 be V₂.

recall that tangential velocity can be related to angular velocity, ω by the following relationship:

V = rω, where V is the tangential velocity, ω is angular velocity and r = radius.

rearranging, we get

ω = V/r

We also know that at any point in the rotation, even though the tangential velocity at 7.17m radius (V₁) will be different from the tangential velocity at 4.01m radius (V₂), their angular velocity will be the same, hence we can equate:

ω₁ = ω₂, or

V₁/r₁ = V₂/r₂ (rearranging)

V₁/V₂ = r₁/r₂ -----(eq 1)

We also know that centripetal acceleration can be expressed in terms of tangential velocity and radius, i.e

a =V²/r

to find the ratio of the centripetal acceleration at the tip and at r=4.01m

a₁/a₂ = (V₁²/r₁) / ( V₂² / r₂) (rearranging & simplify)

= (V₁/V₂)² (r₂ / r₁) (substituting eq1 into equation)

= (r₁/r₂)²(r₂ / r₁) (simplifying)

= (r₁/r₂) (substituting r₁=7.17 and r₂=4.01)

= 7.17 / 4.01

= 1.789

7 0

4 years ago

A 0.23-f capacitor is desired. What area must the plates have if they are to be separated by a 3.8-mm air gap?

tia_tia [17]

The area of the plates must have is(A)= 9.91×10⁷ m²

<h3 /><h3>How can we calculate the value of a area of a capacitor?</h3>

To calculate the the value of a area of the plates of a capacitor, we are using the formula,

C= $\frac{\epsilon_0 A}{d}$

Or, A= $\frac{C\times d}{\epsilon_0}$

Here we are given,

C= The desired capacitance of a capacitor.

= 0.23F

d=distance of separation between the plates.

=3.8mm= 0.0038m.

$\epsilon_0$ = permittivity of the vacuum.

=8.854×10⁻¹²F/m

We have to calculate the area of the plates must have = A m².

Now we put the known values in the above equation, we can get

A= $\frac{C\times d}{\epsilon_0}$

Or, A= $\frac{0.23\times 0.0038}{8.854\times 10^{-12}}$

Or, A= 9.91×10⁷ m²

From the above calculation, we can conclude that the area of the plates must have is(A)= 9.91×10⁷m²

Learn more about Capacitor:

brainly.com/question/13578522

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5 0

2 years ago

The gravitational force law, deduced by Newton in the 1660's, is remarkably similar to Coulomb's law. Recall that the universal

viktelen [127]

Answer:

a. $F=7.83\times 10^{-51} N$

b.Attractive

Explanation:

We are given that

$F=\frac{GM_1M_2}{R^2}$

$G=6.67\times 10^{-11} Nm^2/kg^2$

Mass of an electron, $M_1=9.11\times 10^{-31} kg$

Mass of proton, $M_2=1836\times 9.11\times 10^{-31} kg$

Distance between electron and proton,R= $3.602nm=3.602\times 10^{-9} m$

$1nm=10^{-9} m$

a.Substitute the values then we get

$F=\frac{6.67\times 10^{-11}\times 9.11\times 10^{-31}\times 1836\times 9.11\times 10^{-31}}{(3.602\times 10^{-9})^2}$

$F=7.83\times 10^{-51} N$

b.We know that like charges repel to each other and unlike charges attract to each other.

Proton and electron are unlike charges therefore, the force between proton and electron is attractive.

4 0

3 years ago

Find the resultant of two forces of 4.0N and 6.0N acting at an angle of 160° to each other.

hichkok12 [17]

$\star\sf \overrightarrow{A}=4N$

$\star\sf\overrightarrow{B}=6N$

Angle=160

$\boxed{\sf R=\sqrt{A^2+B^2+2ABcos\theta}}$

$\\ \sf\longmapsto R=\sqrt{4^2+6^2+2(4)(6)cos160}$

$\\ \sf\longmapsto R=\sqrt{16+36+48(-0.93)}$

$\\ \sf\longmapsto R=\sqrt{52-44.6}$

$\\ \sf\longmapsto R=\sqrt{7.4}$

$\\ \sf\longmapsto R=2.7N$

6 0

3 years ago