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kati45 [8]
3 years ago
9

What is the equation for momentum

Physics
2 answers:
Marina CMI [18]3 years ago
5 0

Answer:

p=mv

Explanation:

i looked it up.

s2008m [1.1K]3 years ago
4 0

Answer:

p=mv I think I hope:):)

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An engine with an electronic fuel injection system has high fuel pressure at idle. This could be caused by a:
olga_2 [115]

Answer:

An engine with an electronic fuel injection system has high fuel pressure at idle because of  high manifold vacuum. (option D)

Explanation:

Electronic fuel injection (EFI) system replaced carburetors back in the mid-1980s as the preferred method of supplying air and fuel to engines. The basic difference is that a carburetor uses intake vacuum and a pressure drop in the venturi, to siphon fuel from the carburetor fuel bowl into the engine. Whereas fuel injection system uses pressure to spray fuel directly into the engine.

However, under light load or at idle, a relatively high vacuum exists in the intake manifold. This means less fuel pressure is needed to spray a given volume of fuel through the injector. Under heavy load, engine vacuum drops to near zero.

Therefore, An engine with an electronic fuel injection system has high fuel pressure at idle because of  high manifold vacuum.

5 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST AND EXTRA POINTS!! Super simple I’ve just been sick so I have no clue what’s going on.
Tju [1.3M]

Answer: 12) 1.07 m/s (right) 13) 4.05 m/s 14) 73 m/s 15) 10.9 m/s

Explanation:

12) Conservation of momentum. Momentum is the produce of mass and velocity.

13(2) + 15(-5) = 13(-5) + 15v

v = 1.06666... ≈ 1.07 m/s (right)

13) 18(9) + 22(0) = 18v + 22v

v = 18(9)/40 = 4.05 m/s

14) 0.65(35) + 0.08(0) = 0.65(26) + 0.08v

v = 73.125

15) This is a bit trickier. Let's ASSUME you jump off at 7 m/s relative to the truck. Doing this, we can assume that the reference frame is moving along with the truck at 10 m/s

the conservation of momentum equation becomes

600(0) + 80(0) = 600v + 80(-7)

v = 0.9333333... m/s

adding back the velocity of the reference frame means the truck is now traveling.

10.9333333... ≈ 10.9 m/s

4 0
3 years ago
Identify two everyday phenomena that exhibit diffraction of sound and explain how diffraction of sound applies. Identify two eve
Naya [18.7K]

Answer:

Explanation:

Diffraction is the term used to describe the bending of a wave around an obstacle. It is one of the general properties of waves.

1. Diffraction of sound is the bending of sound waves around an obstacle which propagates from source to a listener. Two of the daily phenomena that exhibit diffraction of sound are:

i. The voices of people talking outside a building can be heard by those inside.

ii. The sound from the horn of a car can be heard by people at certain distances away.

When sound waves are produced, the surrounding air molecules are required for its transmission. This is because sound wave is a mechanical wave which requires material medium for its propagation. When a source produces a sound, the sound waves bend around obstacles on its path to reach listeners.

2. Light waves are electromagnetic waves which can undergo diffraction. Diffraction of light is the bending of the rays of light around an obstacle. Two of the daily phenomena that exhibit diffraction of light are:

i. The shadow of objects which has the umbra and penumbra regions.

ii. The apparent color of the sky.

A ray of light is the path taken by light, and the combination of two or more rays is called a beam. A ray or beam of light travels in a straight line, so any obstacle on its path would subject the light to bending around it during propagation. These are major applications in pin-hole cameras, shadows, rings of light around the sun etc.

Some significant differences between diffraction of light and that of the sound are:

i. Diffraction of light is not as common as that of sound.

ii. Sound propagates through a wider region than light waves.

iii. Sounds are longitudinal waves, while lights are transverse waves.

7 0
3 years ago
A runner starts from rest and in 2 s reaches a speed of 7 m/s. If we assume that the speed changed at a constant rate (constant
PtichkaEL [24]

Answer:

v=3.5\frac{m}{s}

Explanation:

The average speed is defined as:

v=\frac{\Delta x}{\Delta t}

Using the equations for uniformly accelerated motion, we calculate the runner's acceleration:

a=\frac{v_f-v_o}{2}\\a=\frac{7\frac{m}{s}-0\frac{m}{s}}{2s}\\a=3.5\frac{m}{s^2}

Now, we can calculate the distance that the runner travels:

\Delta x=v_0t+\frac{at^2}{2}\\\Delta x=(0\frac{m}{s})(2s)+\frac{3.5\frac{m}{s}(2s)^2}{2}\\\Delta x=7m

Finally, we calculate the runner's average speed:

v=\frac{7m}{2s}\\v=3.5\frac{m}{s}

4 0
3 years ago
When the material in the mantle cools off near the surface then sinks
MatroZZZ [7]
I’m guessing convection currents since you mention mantle and core, reminds me of heat
5 0
3 years ago
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