M = 22.1 g
V = 52.3 mL
D = ?
D = m/V
= 22.1/52.3
= 22.1*10/52.3*10
= 221/523
= 0.4
There. I’m sorry i forgot what exactly was the S.I. unit of density :(
Answer:
The sugar particles are so small that they have dissolved in the water, and can easily pass through the filter.
Answer:
silica + aluminum or silica +magnetism
Explanation:
The oxidation number sulfur in H₂S is -2.
A compound's total number of oxidations must be zero.
The two hydrogen atoms in the chemical hydrogen sulfide, H₂S, each have an oxidation number of +1, making a total of +2. As a result, the compound's sulfur has an oxidation number of -2, and the total number of oxidations is 0.
Assume that the sulfur atom in H₂S has an oxidation number of x.
S be x.
Now,
2+x=0
⇒x=−2
<h3>What is oxidation number?</h3>
The total number of electrons that an atom either receives or loses in order to create a chemical connection with another atom is known as the oxidation number, also known as the oxidation state.
Depending on whether we are taking into account the electronegativity of the atoms or not, these phrases can occasionally have a distinct meaning. Coordination chemistry commonly makes use of the phrase "oxidation number."
<h3>What distinguishes an oxidation number from an oxidation state?</h3>
In contrast to the oxidation state, which indicates how oxidised an atom is in a molecule, the oxidation number describes the charge that the core metal atom will retain once all ligands have been removed.
To know more about oxidation number:
brainly.com/question/13182308
#SPJ4
Answer:
115.2 °C since melting point is an intensive property
Step-by-step explanation:
The melting point of a substance does not depend on how much you have.
For example, the melting point of water is 0 °C, whether it is an ice cube from the refrigerator or in the frozen pond outside.
The freezing point of a substance is an <em>intensive property</em>.
Thus, the melting point of 100 g of sulfur is 115.2 °C because melting point in an intensive property.
