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JulijaS [17]
3 years ago
8

While working out, a man performed 2525 J of work in 19 seconds. What was his power?

Physics
1 answer:
PIT_PIT [208]3 years ago
8 0

Answer:

power  = \frac{work \: done}{time \: passed}  \\   \:  \:  \:   \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:

power=2525J/19S

=132.8947368421JS^-1

=132.9W

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Gre4nikov [31]

Answer: 500 s

Explanation:

Speed v is defined as a relation between the distance d and time t:

v=\frac{d}{t}

Where:

v=3(10)^{8}m/s is the speed of light in vacuum

d=1.5(10)^{11}m is the distance between the Earth and Sun

t is the time it takes to the light to travel the distance d

Isolating t:

t=\frac{d}{v}

t=\frac{1.5(10)^{11}m}{3(10)^{8}m/s}

Finally:

t=500 s

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6 0
3 years ago
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Arte-miy333 [17]
<h3><u>Answer;</u></h3>

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