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UNO [17]
3 years ago
6

A man has three friends help him push his stalled car on a horizontal surface. The friends push with a constant total force of 1

200 N. How far must the car be pushed, starting from rest, so that its final kinetic energy is 4200 J? (Disregard friction.)
Physics
1 answer:
kicyunya [14]3 years ago
3 0

The  Disregard friction of the given problem is 3.5 m

<u>Explanation:</u>

We  have the formula,

Disregard friction= Final kinetic energy / Constant total force

Disregard friction=4200J/1200N

Disregard friction=3.5m

The  Disregard friction of the given problem is 3.5 m

 

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Explanation:

The rotational (angular) speed of an object in circular motion is defined as:

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Here we have two ladybugs, which are located at two different distances from the axis. In particular, ladybug 1 is halfway between ladybug 2 and the axis of rotation. However, since they rotate together with the disk, and the disk is a rigid body, every point of the disk cover the same angle \theta in the same time t: this means that every point along the disk has the same angular speed, and therefore the two ladybugs also have the same angular speed.

On the other hand, the linear speed of the two ladybugs is different, because it follows the equation:

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Learn more about circular motion:

brainly.com/question/2562955

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7 0
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A bus contains a 1440 kg flywheel (a disk that has a 0.63 m radius) and has a total mass of 10200 kg. Calculate the angular velo
CaHeK987 [17]

Answer:\omega =93.51 rad/s

Explanation:

Given

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Conserving Energy i.e.

0.9(Rotational Energy of Flywheel)= change in Kinetic Energy of bus

Let \omegabe the angular velocity of Flywheel

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\omega ^2=21^2\times \frac{10200}{0.9\times 571.536}

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