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jasenka [17]
3 years ago
9

What are the components of a hybrid electric vehicle?

Physics
2 answers:
Brums [2.3K]3 years ago
5 0

"<em>The prime mover of a hybrid vehicle is its main energy source, which generally is one of gasoline, diesel, or fuel cells. The electric motor is one of the most important components in a hybrid vehicle.</em>"

777dan777 [17]3 years ago
5 0

Answer:

Electric Motor.

Gasoline engine.

Fuel Tank.

Generator.

Explanation:

Hybrid electric vehicles as its name suggest it an environmentally friendly Electric vehicle.

The Components of a hybrid electric vehicle are:

  • Electric Motor.
  • Gasoline engine.
  • Fuel Tank.
  • Generator.
  • Batteries.
  • Power split device.

Benefits of hybrid electric vehicles are:

  • Low emission.
  • Environmental friendly.
  • Energy security.
  • Fueling flexibility.
  • Fuel cost saving.

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Answer:

62.5\int\limits^6_0 {(\frac{7}{6}y^{2}-\frac{49}{3}y+56)  } \, dy = 7875 lb

Explanation:

For this problem to be easier to calculate, we can represent the triangle as a right triangle whose right angle is located at the origin of a coordinate system. (See picture attached).

With this disposition of the triangle, we can start finding our integral. The hydrostatic force can be set as an integral with the following shape:

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we know that γ=62.5 lb/ft^{3}

from the drawing, we can determine the height (or depth under the water) of each differential area is given by:

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x can be found by getting the equation of the line, which we'll get by finding the slope of the line and using one of the points to complete the equation:

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when substituting the x and y-values given on the graph, we get that the slope is:

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y-6=-\frac{6}{7}x

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x=-\frac{7}{6}y+7

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\int\limits^6_0{(62.5)(8-y)(-\frac{7}{6}y+7)}\,dy

Now that it's all written in terms of y we can now simplify it, so we get:

62.5\int\limits^6_0 {(\frac{7}{6}y^{2}-\frac{49}{3}y+56)}dy

we can now proceed and evaluate it.

When using the power rule on each of the terms, we get the integral to be:

62.5[\frac{7}{18}y^{3}-\frac{49}{6}y^{2}+56y]^{6}_{0}

By using the fundamental theorem of calculus we get:

62.5[(\frac{7}{18}(6)^{3}-\frac{49}{6}(6)^{2}+56(6))-(\frac{7}{18}(0)^{3}-\frac{49}{6}(0)^{2}+56(0))]

When solving we get:

62.5\int\limits^6_0 {(\frac{7}{6}y^{2}-\frac{49}{3}y+56)  } \, dy = 7875 lb

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