Answer:
D a thermometer
Explanation: It measures and track Celcius and Feirinheit.
Answer:
A.) 1430 metres
B.) 80 seconds
Explanation:
Given that the train accelerates from rest at 1.1m/s^2 for 20s. The initial velocity U will be:
U = acceleration × time
U = 1.1 × 20 = 22 m/s
It then proceeds at constant speed for 1100 m
Then, time t will be
Time = distance/ velocity
Time = 1100/22
Time = 50 s
before slowing down at 2.2m/s^2 until it stops at the station.
Deceleration = velocity/time
2.2 = 22/t
t = 22/2.2
t = 10s
Using area under the graph, the distance between the two stations will be :
(1/2 × 22 × 20) + 1100 + (1/2 × 22 × 10)
220 + 1100 + 110
1430 m
The time taken between the two stations will be
20 + 50 + 10 = 80 seconds
Answer:
a' =4.15 m/s²
Explanation:
Given that
m= 3.2 kg
F₁ = 1.9 i −1.9 j N
F₂=3.8 i −10.1 j N
From second law of Newton's
F(net) = m a
F₁ + F₂ = m x a
1.9 i −1.9 j + 3.8 i −10.1 j = 3.2 a
a = 1.78 i - 3.75 j m/s²
The resultant acceleration a'
a' =4.15 m/s²
Since acceleration is constant
So the distance moved in constant acceleration will be given as
as we know that
t = 17 s
so distance moved is given by
so distance moved will be 170 m
