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3 years ago

Which of the following is not a characteristic of major depressive disorder?

Physics

2 answers:

anastassius [24]3 years ago

8 0

Answer: chest tightness

Explanation: i just took the quiz

Alex787 [66]3 years ago

6 0

D chest tightness

I experienced these the past few days...

but hoped I helped ^_^

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What happens when two positive charges are near each other?

Westkost [7]

If two positive charges are near each other they will repel each other.

7 0

3 years ago

When a point charge of q is placed on one corner of a square, an electric field strength of 2 N/C is observed at the center of t

bearhunter [10]

Answer:

Explanation:

Net electric field at the centre will be zero .

Since all the charges are equal and they all are symmetrically situated around the centre . So the electric field produced by each will cancel out each other and hence the resultant electric field will be zero . It happens because electric field is a vector quantity and therefore it adds up vectorially . All the four electric field will form two pairs , in each pair electric fields are acting in opposite direction . So they all cancel out to zero .

3 0

3 years ago

What type of transfer is affected by color

Mama L [17]

Heat transfer is affected by color.

7 0

3 years ago

________________ can carry thermal energy from object to object, even through empty space.

sdas [7]

Radiation can carry thermal energy.

8 0

3 years ago

During a long jump, an Olympic champion's center of mass rose about 1.2 m from the launch point to the top of the arc. 1) What m

Tanzania [10]

Answer: Minimum speed needed by the Olympic champion at launch if he was traveling at 6.8 m/s at the top of the arc is 11.65 m/s.

Explanation:

Velocity is only in horizontal direction at the top most point which is similar to the velocity in the horizontal direction at the time of launch.

Now, according to the law of conservation of energy the formula used is as follows.

$mgh = \frac{1}{2} mv^{2}_{y}\\v_{y} = \sqrt{2gh}\\= \sqrt{2 \times 9.8 m/s^{2} \times 1.2}\\= 4.85 m/s$

As speed at which the person is travelling was 6.8 m/s. Hence, the initial velocity will be calculated as follows.

$v = \sqrt{v^{2}_{x} + v^{2}_{y}}\\= \sqrt{(6.8)^{2} + (4.85 m/s)^{2}}\\= 11.65 m/s$

Thus, we can conclude that minimum speed needed by the Olympic champion at launch if he was traveling at 6.8 m/s at the top of the arc is 11.65 m/s.

6 0

3 years ago