The average velocity of the whole journey will be total distance covered divided by the total time. It will be approximately equal to 8 m/s. The right answer is option B
<h2>VELOCITY</h2>
Velocity is the distance travelled in a specific direction. While the average velocity of the whole journey will be total distance covered divided by the total time
When driving a Toyota avensis car along a straight road for 16.5km at
50km/h,
The velocity = 50 km/h
Distance = 16.5 km
Use the speed formula to calculate time.
Speed = distance / time
Time = distance / speed
Time = 16.5 / 50
Time = 0.33 s
If over the next 20min, you walked another 2.5km further along the road for a petrol station, Then,
average velocity = Total distance covered divided by total time taken.
Where
The time t = 20/60 = 0.333 h
Total time = 0.33 + 0.3333
Total time = 0.6633333
Total distance = 16.5 + 2.5
Total distance = 19 km
Average velocity = 19 / 0.66333
Average Velocity = 28.64 km/h
Now convert Km/h to m/s
(28.6432 x 1000) / 3600
286432 / 3600
7.956m/s
Therefore, the average velocity of the whole journey from beginning of the drive to the arrival at the filling station will be approximately 8 m/s
Learn more about velocity here: brainly.com/question/6504879
Answer:
Potential Energy is the energy that is waiting to be released like at the top of the roller coaster, Kinetic energy is the energy that is moving the rollercoaster downhill fast.
Three Laws:
The rollercoaster will rest at the top, and then the gears will make it move downhill, and make it stop.
The gears make the rollercoaster move, and in reaction, it pushes back on the gears.
Answer:
a. The horizontal component of acceleration a₁ = 0.68 m/s²
The vertical component of acceleration a₂ = -0.11 m/s²
b. -9.19° = 350.81° from the the positive x-axis
Explanation:
The initial velocity v₁ of the fish is v₁ = 4.00i + 1.00j m/s. Its final velocity after accelerating for t = 19.0 s is v₂ = 17.0i - 1.00j m/s
a. The acceleration a = (v₂ - v₁)/t = [17.0i - 1.00j - (4.00i + 1.00j)]/19 = [(17.0 -4.0)i - (-1.0 -1.0)j]/19 = (13.0i - 2.0j)/19 = 0.68i - 0.11j m/s²
The horizontal component of acceleration a₁ = 0.68 m/s²
The vertical component of acceleration a₂ = -0.11 m/s²
b. The direction of the acceleration relative to the unit vector i,
tanθ = a₂/a₁ = -0.11/0.68 = -0.1618
θ = tan⁻¹(-0.1618) = -9.19° ⇒ 360 + (-9.19) = 350.81° from the the positive x-axis
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Answer:
46 m at 9.5 degrees east of south
Explanation:
