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sertanlavr [38]
3 years ago
15

When preparing the protein standards, we used a tube (t) without protein, but including bradford reagent and an equivalent volum

e of 0.15 m nacl instead of protein. can we just use plain water to prepare tube t instead?
Chemistry
1 answer:
Ulleksa [173]3 years ago
3 0
I think it the correct answer would be no. We cannot use plain water for this since the preparation of such reagent has certain standards to be followed so as to get the best yield for the experiment. So, it would be best to follow these procedures.
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A certain liquid X has a normal boiling point of 111.20 celsius and a boiling point elevation constant Kb=0.95. calculate the bo
Goshia [24]

Answer: the boiling point is = 137.325°C

Explanation:

From the formula: ∆Tb= Kb*m

From the question, Kb= 0.95, m= 27.5, T1= 111.2°C

Substitute into ∆Tb= Kb*m

∆Tb= 0.95*27.5= 26.125

∆Tb= T2-T1

Hence

T2- 111.2=26.125

T2= 26.125+ 111.2= 137.325°C

8 0
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1 point Berny has a 0.15-kilogram candle, a 1.00-kilogram jar, and a 0.25-kilogram candle holder. He places the candle and candl
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Answer:

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Explanation:

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3 years ago
How mant liters at STP are in 0.575 moles of Kr​
gizmo_the_mogwai [7]

Answer:

12.9 L Kr

General Formulas and Concepts:

<u>Chemistry - Gas Laws</u>

  • Using Dimensional Analysis
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Explanation:

<u>Step 1: Define</u>

0.575 mol Kr

<u>Step 2: Identify Conversions</u>

1 mol= 22.4 L at STP

<u>Step 3: Convert</u>

<u />0.575 \ mol \ Kr(\frac{22.4 \ L \ Kr}{1 \ mol \ Kr} ) = 12.88 L Kr

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

12.88 L Kr ≈ 12.9 L Kr

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