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ser-zykov [4K]
3 years ago
15

Convert -225.8°C to K. Enter the correct number of significant figures.​

Chemistry
2 answers:
Len [333]3 years ago
6 0

Answer:

47.3° K

Explanation:

i just looked it up

fomenos3 years ago
4 0

Answer:

47.2K

Explanation:

T(K) = T°C + 273

From the question, we were givenb

T = —225.8°C

T(K) =?

T(K) = T°C + 273

T(K) = —225.8°C + 273

T(K) = 47.2K

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7. Which two substances do geologists use in radiocarbon dating?
Sav [38]

Carbon -14 and Carbon 12 are the two substances geologists use in radiocarbon dating.

Answer: Option B

<u>Explanation: </u>

Radiocarbon dating denotes the determination process of the age of fossils of plants or animals based on the ratio of carbon atoms 14 to 12. Carbon naturally exists in two non-radioactive isotopes, Carbon-12 and Carbon-13 and one radioactive isotope carbon 14. The carbon 14 gets released on continuous cosmic reaction with atmospheric nitrogen.

These carbon 14 will be absorbed by the living plants and from the plants. Then, it will enter inside the animals which consume the plants. But once the plants and animals died, they ceased to intake carbon-14. In their living state, the ratios of carbon atoms 14 to 12 in them tends to similar to the ratio in atmosphere.

But after they die, the ratio of C-14 to C-12 will be varying from the ratio of C-14 to C-12 in atmosphere as the concentration of C-14 will be decreasing in the dead animals and plants. Thus using this ratio, geologists can find the fossil's age.

7 0
4 years ago
Calculate the number of moles of an ideal gas if it occupies 1750 dm3 under 125,000 Pa at a temperature of 127 C.
Phoenix [80]

Hey there!


* Converts 1750 dm³ in liters :


1 dm³ = 1 L so 1750 dm³ = 1750 liters



* Convertes 125,000 Pa in atm :


1 Pa = 9.86*10⁻⁶ atm so 9.86*10⁻⁶ / 125,000 => 1.233 atm


* Convertes 127ºC in K :


127 + 273.15 => 400.15 K


R = 0.082 atm.L/mol.K


Finally, it uses an equation of clapeyron :


p * V = n * R * T


1.233 * 1750 = n * 0.082 * 400.15


2157.75 = n * 32.8123


n = 2157.75 / 32.8123


n = 65.76 moles



hope this helps!



5 0
3 years ago
Read 2 more answers
What is the the term for the final products in a reaction ?
rjkz [21]

Answer:

the final product is called a product

Explanation:

3 0
3 years ago
What is the nuclear binding energy of an atom that has a mass defect of 5.0446
notsponge [240]

Answer:

<em>Option C: 4.54 x </em>10^{11}<em> KJ/mol of nuclei</em>

<em>Note: </em>Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}.

Explanation:

If mass defect is known, then nuclear binding energy can easily be calculated, here's how:

First step is to convert that mass defect into kg.

Mass defect = 5.0446 amu

Mass defect = 5.0466 x 1.6606 x 10^{-27}

Because 1 amu = 1.6606 x 10^{-27} Kg.

<em>Mass defect = 8.383 x </em>10^{-27}<em> kg.</em>

Now, we need to find out it's energy equivalent by using following equation:

Using the equation E = mc²:

where c= 3.00 x 10^{8} m/s²

E = (8.383 x 10^{-27}) x (3.00 x 10^{8})²

E = 7.54 x 10^{-10} J  this energy is in Joules but nuclear binding energy is usually expressed in KJ/mol of nuclei. Let's convert it:

(7.54 x 10^{-10} Joule/nucleus)x(1 kJ/1000 Joule)x(6.022 x 10^{23} nuclei/mol) =  

<em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em>

E = <em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em> So, this is the nuclear binding energy of that atom, which is option  C.

<em>Note:</em> Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}

4 0
4 years ago
Read 2 more answers
Properties of iron, barium, and phosphorus. Explain why nails are made of iron but they are never made of barium or phosphorus.
bearhunter [10]

Nails are made up of iron not of phosphorus and barium.  

As both phosphorous and barium are relatively weaker than iron ,phosphorus breaks easily and barium is also fairly weak. Iron nails are already also not that strong, but their weight and strength are sufficient.  

So the nails are made up of iron.

3 0
3 years ago
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