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ElenaW [278]
3 years ago
7

Do ultraviolet glasses help you?

Physics
1 answer:
Svetllana [295]3 years ago
3 0

Answer:

To really help protect your eyes, a good pair of ultraviolet glasses will reduce the UV rays that reflect off the backside of your lenses by adding an antireflective (AR) coating that cut down the reflection of both UV and visible light.

Explanation:

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How do i do this is hard
Zolol [24]

Answer:

I believe it would be E)none of the above.

Explanation:

7 0
3 years ago
Carbon-14 has a half-life of 5,700 years. How long will it take for 6.25% of the Carbon-14 to be remaining?
kupik [55]

Half life is 5700 years,that is 50%.

6.25% means 1/16 of the life is left.

T^1/16 =T^1/2*4.

5700 × 4 =22800 years

7 0
3 years ago
19. A 0.0340 kg bullet traveling at 120 m/s embeds itself in a 1.24 kg wooden block which
Blababa [14]

Answer: x ≈ 36.3 cm

Explanation:

Conservation of momentum during the collision

0.0340(120) + 1.24(0) = (0.0340 + 1.24) v

v = 3.2025 m/s

The kinetic energy of the block/bullet mass will convert to spring potential

½kx² = ½mv²

x = √(mv²/k)

x = √(1.274(3.2025²) / 99.0)

x = 0.363293... ≈ 36.3 cm

3 0
3 years ago
A ball rolls up a ramp with a velocity of 8.0 m/s. How high up the ramp does it travel?
Flura [38]

The greatest height the ball will attain is 3.27 m

<h3>Data obtained from the question</h3>
  • Initial velocity (u) = 8 m/s
  • Final velocity (v) = 0 m/s (at maximum height)
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Maximum height (h) =?

The maximum height to which the ball can attain can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = 8² – (2 × 9.8 × h)

0 = 64 – 19.6h

Collect like terms

0 – 64 = –19.6h

–64 = –19.6h

Divide both side by –19.6

h = –64 / –19.6h

h = 3.27 m

Thus, the greatest height the ball can attain is 3.27 m

Learn more about motion under gravity:

brainly.com/question/13914606

5 0
2 years ago
Consider two waves defined by the wave functions y1(x,t)=0.50msin(2π3.00mx+2π4.00st) and y2(x,t)=0.50msin(2π6.00mx−2π4.00st). Wh
guapka [62]

Answer:

They two waves has the same amplitude and frequency but different wavelengths.

Explanation: comparing the wave equation above with the general wave equation

y(x,t) = Asin(2Πft + 2Πx/¶)

Let ¶ be the wavelength

A is the amplitude

f is the frequency

t is the time

They two waves has the same amplitude and frequency but different wavelengths.

4 0
3 years ago
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