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Aloiza [94]
3 years ago
12

Calculate the percent error for the following measurements: (a) The density of alcohol (ethanol) is found to be 0.802 g/mL (true

value= 0.798 g/mL). (b) The mass of gold in an earring is analyzed to be 0.837 g (true value =0.864 g).
Chemistry
1 answer:
damaskus [11]3 years ago
6 0

Answer:

a) % E = 0.501 % error between the measured value and the true value

b) % E = 3.125 % error between the measured value and the true value

Explanation:

  • % E = ( ║true value - measured value ║ ) / ( true value ) ) * 100

a) % E = ( ( 0.802 - 0.798 ) / 0.798 ) * 100

⇒ % E = 0.501 %

b) % E = ( ( 0.864 - 0.837 ) / 0.864 ) * 100

⇒ % E = 3.125 %

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6 0
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