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kodGreya [7K]
3 years ago
15

In a photoelectric effect experiment, electrons emerge from a copper surface with a maximum kinetic energy of 1.10 eV when light

shines on the surface. The work function of copper is 4.65 eV.
Which one of the following values is closest to the wavelength of the light?

A) 220 nm

B) 150 nm

C) 360 nm

D) 1100 nm
Physics
1 answer:
Sladkaya [172]3 years ago
6 0

Answer:A) 220 nm

Explanation:

Given

Maximum Kinetic Energy K.E.=1.10 eV

Work Function W=4.65 eV

from Einstein Equation

h\mu =W+K.E.

h\cdot \frac{c}{\lambda }=W+K.E.

h\cdot \frac{c}{\lambda }=4.65+1.10

6.626\times 10^{-34}\cdot \frac{3\times 10^8}{\lambda }=5.75

1 eV=1.6\times 10^{-19} J

thus 5.75 eV=9.2\times 10^{-19} J

\lambda =\frac{6.626\times 10^{-34}\time 3\times 10^8}{9.2\times 10^{-19}}

\lambda =216.06 nm\approx 220 nm

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What is the moving kinetic energy of a 1500kg car moving at 25m/s?
EleoNora [17]

Answer:

<h2>468,750 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

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From the question we have

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We have the final answer as

<h3>468,750 J</h3>

Hope this helps you

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A sports car and a minivan run out of gas and are pushed to the side of the road. Which is easier to push, and why?
Olin [163]

Answer: d

Explanation:

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Suppose an electron is trapped within a small region and the uncertainty in its position is 24.0 x 10-15 m. What is the minimum
Alina [70]

Answer:

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  • Uncertainty in momentum (∆P) = ?
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\longrightarrow \:  \:  \sf\Delta x .\Delta p =  \dfrac{h}{4\pi}

\longrightarrow \:  \:  \sf24 \times  {10}^{ - 15}  .\Delta p =  \dfrac{6.26 \times  {10}^{ - 34}} {4 \times  \frac{22}{7} }

\longrightarrow \:  \:  \sf24 \times  {10}^{ - 15}  .\Delta p =  \dfrac{6.26 \times  {10}^{ - 34}} { \frac{88}{7} }

\longrightarrow \:  \:  \sf24 \times  {10}^{ - 15}  .\Delta p =  \dfrac{6.26 \times  {10}^{ - 34} \times 7} { 8 }

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{43.82 \times  {10}^{ - 34} } { 8  \times 24 \times  {10}^{ - 15} }

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{43.82 \times  {10}^{ - 34} } { 192 \times  {10}^{ - 15} }

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{43.82 \times  {10}^{ - 34}  \times  {10}^{15} } { 192}

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{43.82 \times  {10}^{ -19}   } { 192}

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{4382 \times  {10}^{ - 2}  \times  {10}^{ -19}   } { 192}

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{4382 \times  {10}^{ - 21}   } { 192}

\longrightarrow \:  \:  \sf\Delta p = 22.822\times  {10}^{ - 21}

\longrightarrow \:  \:  \sf\Delta p = 2.2822 \times  {10}^{1} \times  {10}^{ - 21}

\longrightarrow \:  \: \underline{ \boxed{ \red{  \bf\Delta p = 2.2822 \times  {10}^{ - 20}  \:  kg/ms}}}

4 0
3 years ago
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