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ArbitrLikvidat [17]
3 years ago
10

What is the molarity of NaOH if 83.5 mL of NaOH is needed to react with 35.0mL of a 0.275 M solution of H2SO4?

Chemistry
1 answer:
Lostsunrise [7]3 years ago
7 0

Answer:

0.231 mol/L

Explanation:

The first step is to write the balanced equation for this reaction:

H_{2}SO_{4} +2NaOH ===> Na_{2}SO_{4}  +2H_{2}O

The second step is to find the number of moles in the acid:

number of moles = volume * concentration

                             = 0.035 L * 0.275 mol/L

                             = 0.009625 mol

The third step is to use the molar ratio from the balanced chemical equation to find the number of moles of NaOH that can neutralize 0.009625 mol of sulphuric acid.

n(sulphuric acid) : n(sodium hydroxide)

          1                :                   2

0.009625 mol    :                   x

x =  0.01925 mol

Fourth step is to calculate the concentration of sodium hydroxide:

concentration = \frac{number of moles}{volume} = \frac{0.01925}{0.0835} =0.231 mol/L

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Write the name and molecular formula of an organic compounds having its name suffixed with -ol and having 2 carbon atoms in the
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Ethanol C₂H₆O

Explanation:

When ethanol (CH₃-CH₂-OH) is heated in the presence of the sulphuric acid (H₂SO₄) it will produce ethylene (CH₂=CH₂ ) and water (H₂O).

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sulphuric acid

brainly.com/question/867125

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4 0
3 years ago
How many formula units are there in 450 g of Na2S04?
Mashutka [201]

Formula units in 450 g of Na_{2} So_{4} is 1.93 × 10²⁴ formula units.

<u>Explanation:</u>

First we have to find the number of moles in the given mass by dividing the mass by its molar mass as,

$\frac{450 g}{142.04 g/mol} =  3.2 moles

Now, we have to multiply the number of moles of Na₂SO₄ by the Avogadro's number, 6.022 × 10²³ formula units/mol, so we will get the number of formula units present in the given mass of the compound.

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HELP!!!!!
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Answer:

5.17.

Explanation:

<em>∵ [H₃O⁺][OH⁻] = 10⁻¹⁴. </em>

[OH⁻] = 1.5  x 10⁻⁹ M.

∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(1.5  x 10⁻⁹ M) = 6.66 × 10⁻⁶ M.

∵ pH = - log[H₃O⁺]

<em>∴ pH = - log(6.66 × 10⁻⁶ M) = 5.17. </em>

5 0
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Explanation:

The ground state electron configuration of ground state gaseous neutral lead is [Xe].

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