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ArbitrLikvidat [17]
3 years ago
10

What is the molarity of NaOH if 83.5 mL of NaOH is needed to react with 35.0mL of a 0.275 M solution of H2SO4?

Chemistry
1 answer:
Lostsunrise [7]3 years ago
7 0

Answer:

0.231 mol/L

Explanation:

The first step is to write the balanced equation for this reaction:

H_{2}SO_{4} +2NaOH ===> Na_{2}SO_{4}  +2H_{2}O

The second step is to find the number of moles in the acid:

number of moles = volume * concentration

                             = 0.035 L * 0.275 mol/L

                             = 0.009625 mol

The third step is to use the molar ratio from the balanced chemical equation to find the number of moles of NaOH that can neutralize 0.009625 mol of sulphuric acid.

n(sulphuric acid) : n(sodium hydroxide)

          1                :                   2

0.009625 mol    :                   x

x =  0.01925 mol

Fourth step is to calculate the concentration of sodium hydroxide:

concentration = \frac{number of moles}{volume} = \frac{0.01925}{0.0835} =0.231 mol/L

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Answer:

See explanation

Explanation:

According to Bronsted-Lowry, an acid is a proton donor while a base is a proton acceptor.

Hence, if we consider the reaction above, we will notice that for each base there is a conjugate acid and for each acid there is a conjugate base.

For the acid HNO3, its conjugate base is NO3^- while for the acid H3O^+, its conjugate base is H2O.

4 0
2 years ago
Describe Rutherford's contribution to the atomic model.
Nady [450]

Answer:

Rutherford's experiment, also known as

\alpha  - scattering \: experiment

supports the existence of neutrons and the nucleus.

Explanation:

In the above diagram, Rutherford was trying to explain his contributions using thin foils of gold and other metals as targets for alpha particles from a radioactive source.

He observed that the majority of particles penetrated the foil either undeflected or with only a slight deflection. But, every now and then an alpha particle was scattered(or deflected) at a large angle..

According to Rutherford, most of the atoms must be empty space. This explains why the majority of alpha particles passed through through the gold foil with little or no deflection. The atoms positive charges, Rutherford proposed are all concentrated in the Nucleus, <em>which</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>dense</em><em> </em><em>central</em><em> </em><em>core</em><em> </em><em>withi</em><em>n</em><em> </em><em>the</em><em> </em><em>atom</em><em>. </em>

Whenever an alpha particle came close to a nucleus in the scattering experiment, it experienced a large repulsive force and therefore a large deflection. Moreover, an alpha particle coming towards a nucleus would be completely repelled and its direction would be reversed. The positively charged particles in the Nucleus are called Protons.

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4 0
3 years ago
A sample of 3.62 moles of diphosphorous trioxide is
Sindrei [870]

H_3PO_32H_3PO_32H_3PO_3P_2O_3Answer:

B

Explanation:

This question is about stoichiometry. From the balanced equation P_2O_3 + 3H_2O⇒2H_3PO_3, we see that 3 moles of water is needed to react with 1 mole of P_2O_3.

This means that, to fully react 3.62 moles of P_2O_3, we would need 3*3.62 or  10.86 moles of water. However, we only have 6.31 moles, so water is the limiting reactant.

Since 3 moles of water react with 1 mole of P_2O_3, 6.31 moles of water can fully react with 6.31÷3 or 2.1033 moles of P_2O_3.

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5 0
2 years ago
Medical implants and high-quality jewelry items for body piercing are frequently known by a trade name, G23Ti, which means "surg
mrs_skeptik [129]

Answer:

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Explanation:

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This is a stoichiometry Question so in order to be able to solve this question one must have the basic knowledge of stoichiometry, it is advisable that one revise it.

So, let us delve right into the solution of this question. Recall that, the formula for Calculating the number of moles = mass/molar mass.

Hence, the number of moles of titanium,Ti = 64.3/47.87 = 3 moles.

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2 years ago
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Alenkasestr [34]

Answer:

D

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= (3 x 10^8 m/s) / (3 x 10^12 Hz)

= 1 x 10^-4 m

5 0
2 years ago
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