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DENIUS [597]
3 years ago
14

A meter stick A hurtles through space at a speed v = 0.25c relative to you, with its length aligned with the direction of motion

. You stand on Earth and have another meter stick B with its length aligned with the direction of motion of meter stick A. You measure the length of meter stick A to be 1 m. What is the length of meter stick B, L_B, as seen in the rest frame of meter stick A?
Physics
1 answer:
yaroslaw [1]3 years ago
4 0

Answer:

L_0\approx1.0328\ m

Explanation:

Given:

  • relativistic length of stick A, L=1\ m
  • relativistic velocity of stick A with respect to observer, v=0.25c=7.5\times 10^{7}\ m.s^{-1}

<em>Since the object is moving with a velocity comparable to the velocity of light  with respect to the observer therefore the length will appear shorter according to the theory of relativity.</em>

<u> Mathematical expression of the theory of relativity for length contraction:</u>

L=\frac{L_0}{\gamma}

where:

L = relativistic length

L_0= original length at rest

\gamma = Lorentz factor =\frac{1}{\sqrt{1-\frac{v^2}{c^2} } }

\Rightarrow 1=\frac{L_0}{\frac{1}{\sqrt{1-\frac{(0.25c)^2}{c^2} } }}

L_0=\frac{1}{\sqrt{1-\frac{(0.25c)^2}{c^2} } }

L_0\approx1.0328\ m

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v = 40 m/s

In the x direction, the velocity is constant at 30 m/s.

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True

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4 years ago
Consider a steel cable with a diameter of 8.0 mm. Calculatethe stress in the cable when it holds a person weighing 850 N.Report
pishuonlain [190]

Answer:

stress = 16.9 MPa

Explanation:

The stress in the cable can be calculated as:

\text{Stress = }\frac{F}{A}

Where F is the force and A is the area. So, the area can be calculated as:

A=\pi^{}\cdot r^2

Where r is the radius. Since the radius is half the diameter, the radius is 4.0 mm and the area will be equal to:

\begin{gathered} A=3.14(4\operatorname{mm})^2 \\ A=50.24\operatorname{mm}^2 \end{gathered}

Then, replacing the force F by 850 N, and A by 50.24 mm², we get that the stress is equal to:

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7 0
1 year ago
A mass of 100 kg is pulled by a 392 N force in the +X direction along a rough surface (uk=0.4) with uniform velocity v=20 m/s. W
alexdok [17]

Answer:

The total work done will be zero.

Explanation:

Given that,

Mass = 100 kg

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The net force is zero.

Hence, The total work done will be zero by all forces on the object.

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3 years ago
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