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vovangra [49]
3 years ago
5

What codes for the characteristics of an organism?

Chemistry
1 answer:
Minchanka [31]3 years ago
5 0
B: dna cells should be the answer
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Write the chemical formula for carbon tetrachloride and calcium bromide
aliya0001 [1]
Carbon tetra chloride = CCl4

calcium bromide = CaBr2
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2 years ago
How did he know that the nucleus was positively charged?
Harman [31]
'cause alphe-particle which was +ve charge, get repulsion from the atom, so he deducted that.......
8 0
3 years ago
Classify the statements pertaining to elements and compounds as either true or false
Volgvan

Yes Compounds are generally made of two or more atom or ion or species!

TRUE

3 0
3 years ago
Suppose the reaction between nitrogen and hydrogen was run according to the amounts presented in Part A, and the temperature and
andrew11 [14]

Explanation:

Assuming that moles of nitrogen present are 0.227 and moles of hydrogen are 0.681. And, initially there are 0.908 moles of gas particles.

This means that, for N_{2}(g) + 3H_{2}(g) \rightarrow 2NH_{3}

 moles of N_{2} + moles of H_{2} = 0.908 mol

Since, 2 moles of N_{2} = 2 \times 0.227 = 0.454 mol

As it is known that the ideal gas equation  is PV = nRT

And, as the temperature and volume were kept constant, so we can write

        \frac{P(_in)}{n_(in)} = \frac{P_(final)}{n_(final)}

          \frac{10.4}{0.908} = \frac{P_(final)}{0.454
}

       P_(final) = 10.4 \times \frac{0.454}{0.908}

                            = 5.2 atm

Therefore, we can conclude that the expected pressure after the reaction was completed is 5.2 atm.

7 0
3 years ago
The activation energy for a reaction is changed from 184 kJ/mol to 60.5 kJ/mol at 600. K by the introduction of a catalyst. If t
Ahat [919]

Answer:

The catalyzed reaction will take 1,41 s

Explanation:

The rate constant for a reaction is:

k = A e^{-\frac{Ea}{RT}}

Assuming frequency factor is the same for both reactions (with and without catalyst) it is possible to obtain:

{\frac{k1}{k2}} = e^{-\frac{Ea_{2}-Ea_{1}}{RT}}

Replacing:

{\frac{k1}{k2}} = e^{-\frac{60,5kJ/mol-184kJ/mol}{8,314472x10^{-3}kJ/molK*600k}}

{\frac{k1}{k2}} = 5,64x10^{10}

That means the reaction occurs 5,64x10¹⁰ faster than the uncatalyzed reaction, that is 2537 years / 5,64x10¹⁰ = 4,50x10⁻⁸ years. In seconds:

4,50x10⁻⁸ years×\frac{365days}{1year}×\frac{24hours}{1day}×\frac{3600s}{1hour} =<em> 1,41 s</em>

I hope it helps!

6 0
3 years ago
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