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2 years ago

Determine the value of the resistor r so that a current of 0.5a flows through the load.

1 answer:

8 0

What is the value of the voltage? There must be one somewhere.

This might be too simple minded, but I'll give it a voltage of 10 Volts.

R = voltage / Current
R = 10 / 0.5
R = 20 volts.

Perhaps you could post a diagram if this is a Kirchhoff Law Question.

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A ball is dropped from 215m. How long will it take to reach the ground? Use 9.8

valkas [14]

Answer:

The time is $t = 6.62 \ s$

Explanation:

From the question we are told that

The height of the platform where the ball was dropped from is s = 215 m

The acceleration due to gravity is $g = 9.8 \ m/s^2$

Generally from kinematic equations

$s = ut + \frac{1}{2} gt^2$

Here u is the initial velocity of the ball and the value is u = 0 m/s given that the ball was at rest before it was dropped

$21 5 = 0 * t + \frac{1}{2} * 9.8t^2$

=> $21 5 = 4.9t^2$

=> $t^2 = \frac{215}{4.9}$

=> $t = 6.62 \ s$

7 0

3 years ago

Is paper being socked in water a physical or chemical change

jasenka [17]

Physical change and I think you mean soaked.

5 0

3 years ago

Read 2 more answers

A cosmic ray proton moving toward Earth at 5.00 x 107 m/s experiences a magnetic force of 1.7 x 10-16 N. What is the strength of

Blizzard [7]

Answer:

the strength of the magnetic field is 3 x 10⁻⁵ T

Explanation:

Given;

velocity of the cosmic ray, v = 5 x 10⁷ m/s

force experienced by the ray, f = 1.7 x 10⁻¹⁶ N

angle between the ray's velocity and the magnetic field, θ = 45⁰

The strength of the magnetic field is calculated as;

$F = qvB \ sin(\theta)\\\\B = \frac{F}{qv\times sin(\theta)} \\\\where;\\\\B \ is \ the \ strength \ of \ the \ magnetic \ field\\\\q \ is \ the \ charge \ of \ the \ cosmic \ ray \ proton = 1.602 \times 10^{-19} \ C\\\\B = \frac{1.7\times 10^{-16}}{(1.602 \times 10^{-19})\times (5\times 10^7) \times sin \ (45)} \\\\B = 3 \times 10^{-5} \ T$

Therefore, the strength of the magnetic field is 3 x 10⁻⁵ T

7 0

2 years ago

2 Ca + O 2 → 2 CaO What is the product of the reaction

scoray [572]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The product in a chemical reaction is written on the Right side of the arrow, so

the product formed here in given reaction is :

CaO (Calcium Oxide)

5 0

2 years ago

What is the strength of the electric field in a region where the electric potential is constant?

Roman55 [17]

Answer:

Where the electric potential is constant, the strength of the electric field is zero.

Explanation:

As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e

Eₓ = - dV / dx ----------(i)

From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.

Therefore, a constant electric potential means that electric field is zero.

4 0

3 years ago