The statement “Impulse is a vector quantity” is true about Impulse.
Answer: Option B
<u>Explanation:
</u>
The object’s action by applied force in a particular time interval, there happens changing in momentum called impulse. It is denoted by a symbol ‘J’ or ‘imp’ and expressed in a unit ‘Ns’. As impulse depends on the acted force, when a collision arises from front, behind or side, the force’s direction would be differed.
So, from this option A is false as impulse is not a force but changing momentum. The unit is not Newton, it is Newton second (Ns). The force direction differs (impulse direction) for each cases of collision, so option D also false. Hence, option B seems to be correct. Vector quantity deals with both direction and magnitude and important in motion study.
Answer:
Explanation:
In this question we have given
we have to find
We know that
optical path difference for bright fringe is given as
Here,
n is order of fringe
and optical path difference for dark fringe is given as
since the light with wavelength 
produces its third-order bright fringe at the same place where the light with wavelength 
produces its fourth dark fringe
it means
optical path difference for 3rd order bright fringe= optical path difference for forth order dark fringe
Therefore,
...............(1)
Put value of in equation (1)
Answer:
wavelength
Explanation:
the definition of wavelength is the distance between two consecutive waves. with that being said, the point from the crest of one wave to the crest of another would be wave length
Apply the law of conservation of momentum for this situation. The law states that the momentum of a system is constant (in absence of external forces acting on it).
The 'system' in this case are the two skaters. There is no external force on the skaters. Suppose the skaters are initially standing still. The momentum in the system is 0. This value will need to remain constant, even after the mutual push (which is a set of forces from <em>inside</em> the system). So we know that
(total momentum before) = (total momentum after)
Indexing the masses and velocities by the first letter of the skaters' names:
From the last row, you can see that the skaters will have momentum of same magnitude but opposite direction, after the push off. That answers the first question: neither will have a greater momentum (both will have one of same magnitude).
Since Ricardo is heavier, from the above equality it follows that
In words, Paula has the greater speed, after the push-off.
Explanation:
Use the magnitude and direction of each vector to find its components. Add the components that are along the same dimension. Then use Pythagorean theorem and trigonometry to find the magnitude and direction of the resultant vector.
For example, if we have a vector of magnitude A and direction α, and another vector of magnitude B and direction β, then the components of the first vector are:
Ax = A cos α
Ay = A sin α
And the components of the second vector are:
Bx = B cos β
By = B sin β
The resultant vector (we'll call it C) has components:
Cx = Ax + Bx
Cy = Ay + By
The magnitude of the resultant vector is:
C = √(Cx² + Cy²)
And the direction of the resultant vector is:
θ = atan(Cy/Cx)
