1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kolbaska11 [484]
3 years ago
12

What is the 17th element on the periodic table?

Chemistry
2 answers:
Naya [18.7K]3 years ago
5 0
The 17th element would be Chlorine (Cl).
zepelin [54]3 years ago
3 0
Chlorine<span> is in group 17 of periodic table, also called the halogens, and is not found as the element in nature only as a compound. 
Hope I helped Ya!</span>
You might be interested in
how do the properties of compounds compare to the properties of the elements from which they are composed
Crank
<span>The elements that form the compound don't compare because it doesn't matter about the elements when they are combined. The elements that formed it together is completely different than the outcome compound. </span>
6 0
3 years ago
Granite is which pure substance and mixture
DanielleElmas [232]

Window cleaner is ammonia dissolved in water. This is an example of a _______.

6 0
3 years ago
Phosphorite is a mineral that contains plus other non-phosphorus-containing compounds. What is the maximum amount of that can be
8_murik_8 [283]

Phosphorus can be prepared from calcium phosphate by the following reaction:

2Ca_3(PO_4)_2(s)+6SiO_2(s)+10C(s)\rightarrow 6CaSiO_3(s)+P_4(s)+ 10CO(g)

Phosphorite is a mineral that contains Ca_3(PO_4)_2 plus other non-phosphorus-containing compounds. What is the maximum amount of P_4 that can be produced from 2.3 kg of phosphorite if the phorphorite sample is 75% Ca_3(PO_4)_2 by mass? Assume an excess of the other reactants.

Answer: Thus the maximum amount of P_4 that can be produced is 0.345 kg

Explanation:

Given mass of phosphorite Ca_3(PO_4)_2  = 2.3 kg

As given percentage of phosphorite Ca_3(PO_4)_2 is = \frac{75}{100}\times 2.3kg=1.725kg=1725g

moles=\frac{\text {given mass}}{\text {Molar mass}}

{\text {moles of}Ca_3(PO_4)_2=\frac{1725g}{310g/mol}=5.56moles

2Ca_3(PO_4)_2(s)+6SiO_2(s)+10C(s)\rightarrow 6CaSiO_3(s)+P_4(s)+ 10CO(g)

According to stoichiometry:

2 moles of phosphorite gives = 1 mole of P_4

Thus 5.56 moles of phosphorite give= \frac{1}{2}\times 5.56=2.78moles of P_4

Mass of P_4=moles\times {\text {Molar mass}}=2.78mol\times 124g/mol=345g=0.345kg

Thus the maximum amount of P_4 that can be produced is 0.345 kg

5 0
3 years ago
20. Ice wedging is one cause of increased__? (2 wor
Leno4ka [110]
The answe is 56 setup the word primooo
3 0
3 years ago
66.41 g of Copper [Cu] are combusted with 8.56g of Oxygen [O] to produce a
MrMuchimi

The empirical formula of the compound : Cu₂O

<h3>Further explanation</h3>

Given

66.41 g Cu

8.56 g O

Required

The empirical formula

Solution

1. Find mol

  • Cu(Ar 63.5 g/mol)

mol = mass : Ar

mol = 66.41 : 63.5

mol = 1.046

  • O(Ar=16 g/mol)

mol = 8.56 : 16

mol = 0.535

2. mol ratio

Cu : O (divide by smallest mol⇒0.535) :

\tt \dfrac{1.046}{0.535}\div \dfrac{0.535}{0.535}=2\div 1

6 0
3 years ago
Other questions:
  • What hydrocarbons burn completely in an excess of oxygen, the products are
    6·2 answers
  • Bob adds heat to a liquid substance. When enough heat is added,
    13·1 answer
  • Is spilling cake batter a physical or a chemical change?<br>Explain why?
    13·2 answers
  • Drag each tile to the correct box.
    14·1 answer
  • Mechanism with a small activation energy or one with large activation energy​
    10·1 answer
  • Balance equation P2O5 + H20 - - - - &gt; H3PO4<br> Help me.....
    8·1 answer
  • Helpppppppppppppppppppppppppppppppppppppppp
    12·2 answers
  • How many mL of a 2.50 M K2SO4 solution are required to obtain 1.20 moles of<br> K2SO4?
    5·1 answer
  • Certain drugs, such as ssris, block the reuptake of a neurotransmitter into the presynaptic cell. what effect does this have ons
    10·1 answer
  • 1)
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!