Maressa has 150 g of a NaCl solution that has concentration of 15.0 % NaCl (mm). How much NaCl is dissolved in that solution? O
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Answer:
The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is 2:1
Explanation:
According to the consideration, let us first find the ratio of S and O in both the compounds
For SO:
Let us express it as
For SO₂,
Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times
Let us express it as
Now, for the ratio of both the above-calculated ratios,
The required ratio is 2:1
0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.
Explanation:
Data given:
volume of the nitrogen gas = 2 litres
Standard temperature = 273 K
Standard pressure = 1 atm
number of moles =?
R (gas constant) = 0.08201 L atm/mole K
Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law
PV = nRT
rearranging the equation to calculate number of moles:
PV = nRT
n =
putting the values in the equation:
n =
n = 0.091 moles
0.091 moles of nitrogen gas is contained in a container at STP.
The limiting reagent will be Al
<h3>What are limiting reagents?</h3>They are reagents that limit the quantity of products that are formed in reactions.
From the equation of the reaction:
The mole ratio of Al to O2 is 4:3.
With 2 moles of Al and 2 moles of O2, Al becomes limiting while O2 is in excess.
With 2 moles of O2, the amount of Al required should be:
2 x 4/3 = 2.67 moles.
With 2 moles of Al, the amount of O2 required should be:
2 x 3/4 = 1.5 moles
Thus, O2 is in excess by 0.5 moles.
More on limiting reagents can be found here: brainly.com/question/11848702
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