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Serggg [28]
3 years ago
13

Maressa has 150 g of a NaCl solution that has concentration of 15.0 % NaCl (mm). How much NaCl is dissolved in that solution? O

a. 0.05 O b. 1.08 Oc2.25 O d. 225 Oe. None of the above.
Chemistry
1 answer:
Iteru [2.4K]3 years ago
4 0

Answer:

I don't know if option e. is 22,5 g. because that is the correct answer for this. 15% NaCl (mm) gives you the information that in 100 g of solution, you have 15 g of solute. So, if in 100 g of solution you have 15 g of NaCl, in 150 g of solution, how much. Try the rule of three.

Explanation:

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What is the difference between concentrated acid and a weak one?
makkiz [27]

Answer:

Difference between concentrated acid and weak acid :---

  • According to Arrhenius's theory the substances which easily get dissociated into H+ ions when dissolved in water are acids.

  • And the substance which readily gives H+ ions on dissociation (when dissolved in water) are Strong Acid. Examples are HCl , H2SO4 etc.

While,

  • Concentration of acid is just the value of pH. pH is the measurement of concentration of acid or base. The lower the pH, higher the concentration.

  • So strong acid is strong because it gives H+ ions readily in water and Concentration is the value of pH.
7 0
2 years ago
Whats the main difference between a double replacement reaction and a single replacement
aivan3 [116]

Answer:

a single-replacement reaction replaces one element for another in a compound. A double-replacement reaction exchanges the cations, or the anions, of two ionic compounds.

7 0
3 years ago
How many moles are in 7.6 g of Ca
klasskru [66]

Your answer would be 0.024951344877489 but rounding it would be 0.025 moles

7 0
3 years ago
An isotope contains 16 protons 18 electrons and 16 neutrons. what is the identity of the isotope
jarptica [38.1K]

Answer:

Sulfur

Explanation:

You find the identity by looking at the number of protons.  The number of protons never change for an element.

3 0
3 years ago
The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c
netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is 4.58\times 10^{-3}M

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of oxygen gas

C_2\text{ and }p_2 are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used:  1 atm = 760 torr

C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm

Putting values in above equation, we get:

\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M

Hence, the solubility of oxygen gas at 628 torr is 4.58\times 10^{-3}M

4 0
2 years ago
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