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Karolina [17]
3 years ago
12

What is the molairity of a solution that consiste of 4.5 mols of a soluter in a 500 ml solution? Show your work.

Chemistry
2 answers:
cupoosta [38]3 years ago
8 0

the other ans is perfect in explanation the steps to calculate...

BUT theres a single math mistake:

4.5mol/0.5L = 9M n not 0.9M

so 9M is the correct ans

RideAnS [48]3 years ago
3 0

Answer:

0.9 mol/L.

Explanation:

  • Molarity is defined as <em>the number of moles of solute in a 1.0 L of the solution.</em>
  • It can be expressed as: <em>M = n / V(L)</em>

M is the molarity of the solution <em>(mol/L)</em>,

n is the number of moles of solute <em>(n = 4.5 moles)</em>,

V is the volume of the solution <em>(V = 500 ml = 0.5 L)</em>.

  • ∴ The molarity of the solution (M) = n / V = (4.5 mol) / (0.5 L) = 0.9 mol/L.
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Explanation:

For the first part,

 Reaction equation:

         N₂  +  3H₂   →   2NH₃

Given:

Number of moles of NH₃  = 6 moles

Unknown:

Number of moles of N₂  = ?

Solution:

   N₂  +  3H₂   →   2NH₃;

  From the reaction above, we solve from the known specie to the unknown. Ensure that the equation is balanced;

         2 moles of NH₃ is produced from 1 mole of N₂

        6 moles of NH₃ will be produced from \frac{6}{2}  mole of N₂

                                                                      = 3moles of N₂

The number of moles of N₂ is 3 moles

ii.

Given parameters:

Number of moles of sulfur = 2.4moles

Molar mass of sulfur  = 32.07g/mol

Unknown:

Mass of sulfur  = ?

Solution:

The number of moles of any substance can be found using the expression below;

 Number of moles  = \frac{mass}{molar mass}

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