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Brums [2.3K]
2 years ago
12

How many atoms are present in 7.50 mol of chlorine atoms? _

Chemistry
1 answer:
vodomira [7]2 years ago
6 0

Answer:

4.52 x 10²⁴ atoms Cl

Explanation:

A mole is a name that means a certain number like a dozen means 12. 1 mole of chlorine atoms is 6.022 x 10²³ chlorine atoms. The unit conversion is 6.022 x 10²³/mol.

7.50molCl*\frac{6.022 x 10^{23} atomsCl}{1molCl} = 4.5165*10^{24} atomsCl

Round to 4.52 x 10²⁴ atoms Cl for the correct number significant figures.

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8. A sample of chloroform is found to contain 24.0 g of carbon,212.8 g of chlorine, and 2.02 g of hydrogen. If a second sample o
Misha Larkins [42]

Answer:

595.5

Explanation:

chloroform with 24.0 g C was 238.2 g

24g/238.2g= 60g/x

595.5

4 0
3 years ago
What is the complete ionic equation for H2SO4(aq) + Cal2(aq) -> CaSO4(s) + 2HI(aq)?
eimsori [14]
2H(+) + SO4(2-) + Ca(2+) + 2I(-) -> CaSO4(s) + 2H(+) + 2I(-)
The signs in brackets are the subscripts for the charge of the ion. This is the complete ionic equation. The net ionic equation is:
Ca(2+) + SO4(2-) -> CaSO4
6 0
3 years ago
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The weight of an object is constant. true false
Dahasolnce [82]
False weight is dependent on the force of gravity 
 
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3 years ago
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Calculate the molarity of a solution obtained dissolving 10.0 g of cobalt(Ⅱ) bromide tetrahydrate in enough water to make 450 mL
Vladimir [108]

Answer:

<em><u>The molarity of the CoBr2•4H2O solution is  7.64 × 10-2 M</u></em>

Explanation:

Cobalt (II) bromide tetrahydrate

• Cobalt - A transition metal with Roman numeral (II) → charge: +2 → Co2+

• Bromide - anion from group 7A → -1 charge → symbol: Br-

• Tetrahydrate- tetra- means 4 and hydrate is H2O

The chemical formula of the compound is: CoBr2•4H2O

We then need to determine the number of moles of CoBr2•4H2O since this is the only information missing for us to find molarity. Notice that the volume of the solution is already given.

We’re given the mass of CoBr2•4H2O. We can use the molar mass of CoBr2•4H2O4 to find the moles.

•The molar mass of CoBr2•4H2O is:

CoBr2•4H2O  

1 Co x 58.93 g/mol Co = 58.93 g/mol

2 Br x 79.90 g/mol Br = 159.80 g/mol

8 H  x 1.008 g/mol H = 8.064 g/mol

4 O  x 16.00 g/mol O = 64.00 g/mol

________________________________________

                           Sum = <u>290.79 g/ mo</u>

The moles of CoBr2•4H2O is:

= 10.0 g CoBr2•4H2O x  \frac{ 1 mol  CoBr_2 . 4H_2O}{290.79 g CoBr_2 .  4H_2O}

= <u>0.0344  mol CoBr2•4H</u>

We know that the volume of the solution is 450 mL.

We can now calculate for molarity:

Convert mL to L → 1 mL = 10-3 L

Formula:

Molarity (M)= Mole of solute / Liters of solution

= 0.0344  mol CoBr2•4H  / 450 mL x 1 ml / 10^ -3 L

= 0.0764

=  7.64 × 10-2 mol/L

8 0
3 years ago
What is the limiting reactant for the following balanced equation when 9 moles of AlF3 are mixed with 12 miles of O2?
tamaranim1 [39]
<h2>Answer:AlF_{3} </h2>

Explanation:

The chemical equation of the reaction that occurs when AlF_{3} reacts with O_{2} is

4AlF_{3}+3O_{2}→2Al_{2}O_{3}+6F_{2}

4 moles of AlF_{3} requires 3 moles of O_{2}.

1 mole of AlF_{3} requires \frac{3}{4} moles of O_{2}.

Given that we have 9 moles of AlF_{3}.

9 moles of AlF_{3} requires \frac{3}{4}\times 9=6.75 moles of O_{2}.

But we have 12 moles of O_{2}.

So,AlF_{3}  will be consumed first.

So,AlF_{3}  is the limiting reagent.

3 0
3 years ago
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