1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marshall27 [118]
3 years ago
14

Balance the following equation by redox method H2S + H2 O2 gives S + H2O

Chemistry
1 answer:
Maurinko [17]3 years ago
5 0

\text{H}_2\stackrel{-2}{\text{S}} + \text{H}_2\stackrel{-1}{\text{O}_2} \to \; \stackrel{0}{\text{S}} + 2\; \text{H}_2\stackrel{-2}{\text{O}}

<h3>Explanation</h3>

Find the oxidation state for each element.

The oxidation state of H is +1 in most compounds.

  • The S atom in H₂S is bonded to two H atoms. The oxidation state of S in H₂S will be -(2 × (+1)) = -2.
  • Two O atom in H₂O₂ are bonded to two H atoms. On average, the oxidation state for each O atom in H₂O₂ will be - 1/2 × (2 × (+1)) = -1.
  • S has an oxidation state of 0 when it is not bonded to any other element;
  • The O atom in H₂O is bonded to two H atoms. The oxidation state of O in H₂O will be -(2 × (+1)) = -2.

Changes in oxidation states:

  • S: from -2 to 0.
  • O: from -1 to -2.

Each S atom will reduce two O atoms. There are two O atoms in each H₂O₂ molecule. There's only one S atom in each H₂S molecule. As a result, pairing one H₂O₂ with one H₂S will balance the change in oxidation state.

Each H₂O₂ contains two O atoms. The two O atoms will produce two H₂O molecules. Each H₂S molecule will lead to one S molecule. Thus the coefficient for H₂O will be two and the coefficient for the rest three species will be one.

You might be interested in
The energy necessary for photosynthesis to take place is provided by
AfilCa [17]

Answer:

The Sunlight

Oxegyn

Heat in soi

Explanation:

7 0
2 years ago
Read 2 more answers
GOOD MORNING GUYS☕☕☕☕​
Vinvika [58]

Answer:

GOOD MORNING DIDI be happy

8 0
2 years ago
Read 2 more answers
A sample of aluminum is placed in a 25-ml graduated cylinder containing 10.0 ml of water. the level of the water rises to 18.0 m
OLga [1]
To determine the mass of the sample, first find the volume difference after and before the aluminum was placed, the volume change is equal to the volume of the submerged object, in this case aluminum.

Then knowing volume of aluminum and the density of it, we can solve for the mass.

D = m/v

Dv = m

2.7 g/ml • 8 ml = 21.6 grams.
5 0
3 years ago
Read 2 more answers
Which of the following has the greatest influence on the size and force of waves?
svlad2 [7]
Wind speed bc The faster the wind, the longer it blows, or the farther it can blow uninterrupted, the bigger the waves.
3 0
3 years ago
Read 2 more answers
A piston in a heat engine does 500 joules of work, and 1,400 joules of heat are added to the system. Determine the change in int
Ira Lisetskai [31]
The change is that the piston gets hotter? (Theres more heat in it)
8 0
3 years ago
Other questions:
  • Draw the curved arrow mechanism to show the conversion of hex-1-ene and CH3CH2OH in acidic solution into 2-ethoxyhexane. Follow
    13·1 answer
  • What are the advantages of adulteration​
    5·1 answer
  • Which type of bond results when one or more valence electrons are transferred from one atom to another?
    6·1 answer
  • Lipids that are liquid at room temperature are known as ____.
    8·1 answer
  • A titanium cube contains 3.10•10^23 atoms. The density of a titanium is 4.50g/cm^3. What is the edge length of the cube?
    6·1 answer
  • What would a substance that could undergo condensation polymerization most likely have?
    11·2 answers
  • Currently proven global reserves are expected to be largely exhausted within the next 50 years. Uranium-238 A Coal B Natural gas
    14·1 answer
  • What must be part of a quantitative observation?
    13·2 answers
  • Cu^2+ + No2^-<br>what is the formula​
    15·1 answer
  • Which isoelectronic series is correctly arranged in order of increasing radius?.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!