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marshall27 [118]
3 years ago
14

Balance the following equation by redox method H2S + H2 O2 gives S + H2O

Chemistry
1 answer:
Maurinko [17]3 years ago
5 0

\text{H}_2\stackrel{-2}{\text{S}} + \text{H}_2\stackrel{-1}{\text{O}_2} \to \; \stackrel{0}{\text{S}} + 2\; \text{H}_2\stackrel{-2}{\text{O}}

<h3>Explanation</h3>

Find the oxidation state for each element.

The oxidation state of H is +1 in most compounds.

  • The S atom in H₂S is bonded to two H atoms. The oxidation state of S in H₂S will be -(2 × (+1)) = -2.
  • Two O atom in H₂O₂ are bonded to two H atoms. On average, the oxidation state for each O atom in H₂O₂ will be - 1/2 × (2 × (+1)) = -1.
  • S has an oxidation state of 0 when it is not bonded to any other element;
  • The O atom in H₂O is bonded to two H atoms. The oxidation state of O in H₂O will be -(2 × (+1)) = -2.

Changes in oxidation states:

  • S: from -2 to 0.
  • O: from -1 to -2.

Each S atom will reduce two O atoms. There are two O atoms in each H₂O₂ molecule. There's only one S atom in each H₂S molecule. As a result, pairing one H₂O₂ with one H₂S will balance the change in oxidation state.

Each H₂O₂ contains two O atoms. The two O atoms will produce two H₂O molecules. Each H₂S molecule will lead to one S molecule. Thus the coefficient for H₂O will be two and the coefficient for the rest three species will be one.

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Answer:

P = 30.1 atm

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