Answer:
32.52 N
Explanation:
F-F' = ma.................. Equation 1
Where F = Force needed to pull the block, m = mass of the block, a = acceleration of the block, F' = Frictional force of the surface acting on the blcok
F = ma+F'
But,
F' = μmg
Where g = acceleration due to gravity, μ = coefficient of static friction
F = ma+μmg.................... Equation 2
Given: m = 6.0 kg, a = 1.5 m/s², μ = 0.40
Constant: g = 9.8 m/s²
Substitute these values into equation 2
F = 6(1.5)+6(9.8)(0.4)
F = 9+23.52
F = 32.52 N
Answer:
a) 6.1 m
b) 4.6 s
c) 1.326 m/s
d) 0.325 m
Explanation:
a) The wave length is the distance between 2 crests λ = 6.1m
b) The period of the wave is the time it takes from the lowest point to the next lowest point, which is twice the time it takes from the lowest point to the highest point = 2*2.3 = 4.6 s
c) The speed of the wave is the distance per unit of time, or wave length over period = 6.1 / 4.6 = 1.326 m/s
d)The amplitude A is half the distance from the highest point to the lowest point = 0.65 / 2 = 0.325 m
Answer:
The object with a higher mass has three times the kinetic energy of the less massive object.
We know that K.E.= 1/2 mv²
mass of first object = 1kg
speed = v
So K.E. = 1/2mv²
= 1/2 × (1) × v²
=
Now the mass of second body = 3kg
speed = v
So K.E. = 1(3)v²/2
=
now
K.E of first / KE of 2nd
I think C because it's the only one with a an angle T of 30° (The string)