Answer:
16.5moles of CO2
Explanation:
Molar mass of O2 is 32g/Mol
No of mole = 880/32 = 27.5 moles
27.5 Mol of O2 gives X mole of CO2
5 mole of O2 gives 3 moles of CO2
No of mole of CO2 = (27.5×3)/ 5 = 16.5moles
Answer:
A 12.630 bar of chocolate contains 8315 milligrams of sugar
Explanation:
From the basics of conversion, we can find that:
1 gram is equal to 1000 mg
Using cross multiplication, we can find how many milligrams are present in 8.315 grams as follows:
1 gram .............> 1000 mg
8.315 grams ....> ?? mg
amount in milligrams = (8.315*1000) / 1 = 8315 milligrams
Hope this helps :)
<u>Answer:</u> 1.2 moles of carbon dioxide is produced for the given value of oxygen.
<u>Explanation:</u>
The chemical reaction for the combustion of acetylene follows the equation:
By stoichiometry of the reaction:
5 moles of oxygen produces 4 moles of carbon dioxide.
So, 1.5 moles of oxygen will produce = 
of carbon dioxide.
Hence, 1.2 moles of carbon dioxide is produced for the given value of oxygen.
Theyre the big bunched up group in the middle of the periodic table
