How much work output can a 150hp snowmobile do in 15 seconds if it is 18 % efficiency?
1 answer:
The work output is
Explanation:
The power of the snowmobile is
Keeping in mind that
We can convert it into Watts:
The energy used by the snowmobile can be found as follows:
where
P = 111,900 W is the power used
t = 15 s is the time interval
Substituting,
However, the snowmobile is 18% efficient: this means that only 18% of this energy is converted into useful work. Therefore, the work output is
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Answer:
15.07 ksi
Explanation:
Given that:
Pitch (P) = 5 teeth/in
Pressure angle () = 20°
Pinion speed ( ) = 2000 rev/min
Power (H) = 30 hp
Teeth on gear () = 50
Teeth on pinion () = 20
Face width (F) = 1 in
Let us first determine the diameter (d) of the pinion.
Diameter (d) =
=
= 4 in
From the values of Lewis Form Factor Y for ( ) = 20 ; at 20°
Y = 0.321
To find the velocity (V); we use the formula:
V = 2094.40 ft/min
For cut or milled profile; the velocity factor can be determined as follows:
= 2.0472
However, there is need to get the value of the tangential load, in order to achieve that, we have the following expression
Finally, the bending stress is calculated via the formula:
15.07 ksi
∴ The estimate of the bending stress = 15.07 ksi
Answer:
Height.
Explanation:
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
Where,
P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Hence, the property of the object (having a mass of 5 kilograms) which must differ to have different gravitational potential energies is the height from which they are falling from.
The object having the higher height would have a greater gravitational potential energy than the lower object.