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RUDIKE [14]
3 years ago
7

Using resonance, select the most acidic protons in the hexane-2,4-dione molecule. The most acidic proton is the one that, upon r

emoval, will yield the most stable conjugate base.
Check all that apply.
[Hexane-2,4-dione molecule with protons numbered as follows according to IUPAC nomenclature: protons on C1 are numbered 1 through 3, protons on C3 are numbered 4 and 5, protons on C5 are numbered 6 and 7, protons on C6 are numbered 8 through 10.]

Check all that apply.

Protons 1, 2, or 3
Protons 4 or 5
Protons 6 or 7
Protons 8, 9, or 10

Chemistry
1 answer:
kondor19780726 [428]3 years ago
5 0

Answer:

Protons 4 or 5 are most acidic.

Explanation:

As mentioned there are four types of hydrogen in Hexane-2,4-dione.

The numbering are shown in the figure for your better understanding.

As shown in the figure if we remove the proton from carbon number 3 (protons number 4 or 5), it will result in formation of a carbanion. This carbanion is stabilized due to presence of -I group oxygen and there is possibility of resonance (as shown).

Thus protons 4 or 5 are most acidic.

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Sulfur dioxide gas (SO2) and oxygen gas (O2) react to form the liquid product of sulfur trioxide (SO3). How much sulfur dioxide
taurus [48]
1) Balanced chemical equation:

2SO2 (g) +  O2 (g) -> 2SO3 (l)

2) Molar ratios

2 mol SO2 : 1 mol O2 : 2 mol SO3

3) Convert 6.00 g O2 to moles

number of moles = mass in grams / molar mass

number of moles = 6.00 g / 32 g/mol = 0.1875 mol O2.

4) Use proportions with the molar ratios

=> 2 moles SO2 / 1 mol O2 = x / 0.1875 mol O2

=> x = 0.1875 mol O2 * 2 mol SO2 / 1 mol O2 = 0.375 mol SO2.

5) Convert 0.375 mol SO2 to grams

mass in grams = number of moles * molar mass

molar mass SO2 = 32 g/mol + 2*16 g/mol = 64 g/mol

=> mass SO2 = 0.375 mol * 64 g / mol = 24.0 g

Answer: 24.0 g of SO2 are needed to react completely with 6.00 g O2.
7 0
3 years ago
A compound is determined to have the empirical formula C2OH4. If the molar mass of the compound is 132 g/mol, determine the mole
8_murik_8 [283]

Answer: The molecular formula will be C_6O_3H_{12}

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.  

Empirical weight of C_2OH_{4} is 12\times 2+16\times 1+1\times 4=44g

Molecular mass of compound is = 132 g

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{132}{44}=3

The molecular formula will be=3\times C_2OH_4=C_6O_3H_{12}

5 0
3 years ago
How many neutrons are in titanium
strojnjashka [21]

Titanium has an atomic number of 22, which means it has 22 protons and 22 electrons. About 73.8 percent of natural titanium exists as the isotope Ti-48, which contains 26 neutrons.

4 0
3 years ago
You have just completed assaying the change in absorbance for an enzyme. The initial absorbance was 0.022; the absorbance after
Hitman42 [59]

Answer:

The answer is 0.844/10 minutes

Explanation:

You have an enzyme that catalizes a reaction which gives a product that can be quantified by an absorbance measurement. The more reaction time, the more product quantity and higher absorbance.

The rate of the reaction is the change in products quantity per time unit. As you are using the absorbance as a measure of the product quantity, you can calculate the rate as the change in absorbance (ΔA) per time (in minutes) as follows:

rate= ΔA/time

rate= (final absorbance - initial absorbance) /minutes

rate= (0.444-0.022)/5 min

rate= 0.422/5 min

In 10 minutes will be :

rate= 0.844/10 min

Commonly, a rate is the relation between two quantities measured in different units. For example, the speed of a car is the change in meters (traveled distance) per time (m/s or km/h). For an enzyme, is the same (quantity of product/time).

4 0
3 years ago
Examine this reaction:
Alina [70]

Answer:

The normal amount of disaccharide would be produced, but fewer monosaccharides would be produced.

Explanation:

The first reaction, the conversion of starch into disaccharides, is catalyzed by the enzyme amylase. <u>Since amylase is present in a normal amount, a normal amount of disaccharides will be produced.</u>

In the second reaction, these disaccharides will be transformed into monosaccharides by a disaccharidase. However, since t<u>here is less disaccharidase, there will be fewer monosaccharides produced than if it was a normal amount of amylase.</u>

8 0
3 years ago
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