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3 years ago

When determining the motion of the planets in the solar system, what is a good reference point to use? Explain

2 answers:

7 0

The center of the sun is a good reference point when discussing
the motions of the planets.

When we examine the motions of the planets relative to the sun,
the nature of their elliptical orbits is clearly revealed. We also
see the influence of the planets on other smaller bodies, like
their moons, and the comets and asteroids.

We know that the sun is orbiting the center of the Milky Way Galaxy,
and dragging the whole solar system along with it. But if we ignore
that, and study the motions of solar-system objects relative to the
sun, then the motions are a lot simpler, and easier to understand.

FrozenT [24]3 years ago

3 0

The sun. The planets actually move around the sun in a circumduction system, which is when their orbiting position around the sun while moving through space. The planets are continously moving at a rate concurrent with their proximity in regards to the sun as the sun's gravity pulls them while moving.

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Sapting Leng You have a string with a mass of 13.7 q. You stretch the string with a force of 8.39 N, giving it a length of 1.87

marshall27 [118]

Answer:

a) $\lambda=0.935\ \textup{m}$

b) $f=36.19\approx 36\ \textup{Hz}$

Explanation:

Given:

String vibrates transversely fourth dynamic, thus n = 4

mass of the string, m = 13.7 g = 13.7 × 10⁻¹³ kg

Tension in the string, T = 8.39 N

Length of the string, L = 1.87 m

a) we know

$L= n\frac{\lambda}{2}$

where,

$\lambda$ = wavelength

on substituting the values, we get

$1.87= 4\times \frac{\lambda}{2}$

$\lambda=0.935\ \textup{m}$

b) Speed of the wave (v) in the string is given as:

$v =f\lambda$

also,

$v=\sqrt\frac{T}{(\frac{m}{L})}$

equating both the formula for 'v' we get,

$f\lambda=\sqrt\frac{T}{(\frac{m}{L})}$

on substituting the values, we get

$f\times 0.935=\sqrt\frac{8.39}{(\frac{13.7\times 10^{3}}{1.87})}$

$f=\frac{33.84}{0.935}$

$f=36.19\approx 36\ \textup{Hz}$

5 0

3 years ago

The top priority in a lab setting is

SpyIntel [72]

The answer is a.safety

5 0

3 years ago

A 0.023 kg golf ball moving at 18.9 m/s crashes through the window of a house in 5.4 × 10−4 s. After the crash, the ball contin-

PolarNik [594]

Force can be expressed as the time-rate change of momentum

Mathematically, Force = Change in momentum/change in time

Change in momentum = m(10.1-18.9) = -0.2024

Force = -2024/5.4 = -375N(approx)

The significance of the '-' sign is that the direction of force is the opposite that of the direction of our velocities since we assumed them to be positive.

Also this is the force on the ball, the force on the window will be equal and opposite.

7 0

3 years ago

In 5 seconds a car moving in a straight line increases its speed form

marusya05 [52]

Answer:

10,800 m (^2)

Explanation:

<u>234,000 m/s - 180,000 m/s</u> = 10,800 m (^2)

5 0

3 years ago

In 1656, the Burgmeister (mayor) of the town of Magdeburg, Germany, Otto Von Guericke, carried out a dramatic demonstration of t

Tanzania [10]

The force required to pull the two hemispheres apart 53696.25N and the minimum number of horses required is 37 .

( Note: 1 millibar=100 N/m2. One atmosphere is 1013 millibar = 1.013×105 N/m2 )

(1)The contact area between the hemispheres is (π x 0.430²) = 0.5805m²

Pressure difference = (940 - 15) = 925millibars.

(925 x 100) = 92,500N/m^2.

(92500 x 0.5805) = 53696.25N. is the force required to part the hemispheres.

(2) $\frac{53696.25N}{1450N}$ = 37 horses for each side .

37 + 37 = 74 horses will be required.

Force is something which can change the motion of an object, stop it or move it, change its shape or size with it. There are two types of forces, contact forces and non-contact forces. Here, it is a contact force at first, then when the horses come it becomes non-contact force.

Learn more about force here:-

brainly.com/question/13191643

#SPJ1

6 0

1 year ago