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Hatshy [7]
4 years ago
14

When determining the motion of the planets in the solar system, what is a good reference point to use? Explain

Physics
2 answers:
Strike441 [17]4 years ago
7 0

The center of the sun is a good reference point when discussing
the motions of the planets. 

When we examine the motions of the planets relative to the sun,
the nature of their elliptical orbits is clearly revealed.  We also
see the influence of the planets on other smaller bodies, like
their moons, and the comets and asteroids. 

We know that the sun is orbiting the center of the Milky Way Galaxy,
and dragging the whole solar system along with it.  But if we ignore
that, and study the motions of solar-system objects relative to the
sun, then the motions are a lot simpler, and easier to understand.

FrozenT [24]4 years ago
3 0
The sun. The planets actually move around the sun in a circumduction system, which is when their orbiting position around the sun while moving through space. The planets are continously moving at a rate concurrent with their proximity in regards to the sun as the sun's gravity pulls them while moving.

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How does size of an object affect its gravity
irakobra [83]

Answer:

the more particles packed together the faster it falls

Explanation:

the mass + the 1 constant g-force = the speed without adding air resistance

6 0
3 years ago
12) A neutral atom has two, eight, eight electrons in its first, second, and third energy levels.This information ________.
pentagon [3]

Answer:

C.

Explanation:

Option C

The information given in the question tells us about the number of electrons in an atom and also the number of shells in the atom. So, we will come to know about the atomic number, size and chemical properties of the atom. But we cannot determine atomic mass. Atomic mass is a function of number of neutrons and protons.

3 0
3 years ago
1. An object (m = 500 g) with an initial speed of 0.2 m/s collides with another object (m = 1.5 kg) which was at rest before the
Anettt [7]

Answer:

Explanation:

1 )

We shall apply conservation of momentum law to solve the problem.

mv = ( M +m) V , m and M are masses of small and large object , v is the velocity of small object before collision and V is the velocity of both the objects together after collision .

.5 x .2 = (1.5 + .5)V

V = .05 m /s

2 ) We shall use formula for velocity of object after elastic collision as follows

v₁ = \frac{(m_1-m_2)}{(m_1+m_2)} u_1+\frac{2m_2u_2}{(m_1+m_2)}

m₁ and m₂ are masses of first and second object u₁ and u₂ are their initial velocity and v₁ and v₂ are their final velocity.

Putting the values

= \frac{(200-1000)}{(1000+200)} \times 1 +\frac{2 \times1000\times0}{(1000+200)}

= - .66 m /s

Since the sign is negative so it will be in opposite direction .

4 0
3 years ago
2. What is a mirror? How does it work?​
Murljashka [212]

Answer:

a mirror is a glass which reflects the light falls on it ok

Explanation:

just put a light and see ok

please mark me as brainlist

5 0
3 years ago
A cannonball is launched from the ground at an angle of 30 degrees above the horizontal and a speed of 30 m/s. Ideally (no air r
marusya05 [52]

As we know that here no air resistance while ball is moving in air

So here we will say that

initial total energy = final total energy

KE_i + U_i = KE_f + U_f

here we know that

Ui = U_f = 0 (as it will be on ground at initial and final position)

so we will say

KE_i = KE_f

since mass is always conserved

so we will say that final speed of the ball must be equal to the initial speed of the ball

so we have

v_f = v_i = 30 m/s

6 0
3 years ago
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