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ElenaW [278]
3 years ago
6

A scientist working with Polonium-210 detects radiation when the nucleus decays. The radiation emitted has very little penetrati

ng power and is deflected toward the negative terminal in a magnetic field. Which type of radiation is being emitted?
Answer
alpha
beta
gamma
positron
Physics
2 answers:
mezya [45]3 years ago
8 0

Answer:

alpha

Explanation:

As unstable nuclei breaks into some other nuclei in order to attain stability. We will have three type of nuclei decay as following

1). Alpha Decay = it is positively charged high speed helium nuclei which will have energy in form of kinetic energy. Since these are heavy nuclei so penetration power of them is small and they are positively charged

2) Beta Decay = In this type of decay we will have negatively charged electrons released by the unstable nuclei and they move with high energy as they are of lesser mass. Penetration power of beta is more than alpha

3) Gamma Decay = It is neutral and massless photons which contains high energy. Penetration power of gamma is highest among all.

So here as we know that radiation particle is deflected towards negative terminal so it must be a positive particle so here correct answer must be

alpha

Anton [14]3 years ago
6 0
The correct answer would be the first option. Based on the given description above, the type of radiation that is being emitted is ALPHA RADIATION. Alpha radiation is the type of radiation having the lowest penetrative power. Take note that <span>Gamma is stronger than Beta is stronger than Alpha. Hope this answer helps. Have a great day!</span>
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Write a 5-8 sentence summary on Earthquakes.
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Answer:

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3 0
3 years ago
A ball is kicked at a speed of 16m/s at 33° and it eventually returns to ground level further down field.
saw5 [17]

Hi there!

We can begin by calculating the time taken to reach its highest point (when the vertical velocity = 0).

Remember to break the velocity into its vertical and horizontal components.

Thus:

0 = vi - at

0 = 16sin(33°) - 9.8(t)

9.8t = 16sin(33°)

t = .889 sec

Find the max height by plugging this time into the equation:

Δd = vit + 1/2at²

Δd = (16sin(33°))(.889) + 1/2(-9.8)(.889)²

Solve:

Δd = 7.747 - 3.873 = 3.8744 m

4 0
3 years ago
Read 2 more answers
WORTH 50 POINTSSSS!!!!!!!! don't lie either if you do I will report your answer and get my points back idc !!!!!!
BARSIC [14]

Answer:

b

Explanation:

3 0
2 years ago
A 3.30 x 10-2-kg block is resting on a horizontal frictionless surface and is attached to a horizontal spring whose spring const
avanturin [10]

Answer:

0.17547 m

Explanation:

m = Mass of block = 3.3\times 10^{-2}\ kg

v = Velocity of block = 10.8 m/s

k = Spring constant = 125 N/m

A = Amplitude

The kinetic energy of the system is conserved

\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow \\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{3.3\times 10^{-2}\times 10.8^2}{125}}\\\Rightarrow A=0.17547\ m

The amplitude of the resulting simple harmonic motion is 0.17547 m

6 0
3 years ago
What mRNA sequence would result from the following DNA sequence?
Nezavi [6.7K]

Answer:

UAC CUG AGG AUC

Explanation:

<em>The mRNA sequence from ATG GAC TCC TAG DNA sequence would be </em><em>UAC CUG AGG AUC.</em>

<u>According to Chargaff's base pairing rule, the purine bases always pair with pyrimidine bases. Specifically, Adenine base must pair with Thymine base while Guanine base must pair with Cytosine base. In RNA, Thymine base is replaced with Uracil base.</u>

Hence:

ATG   GAC   TCC   TAG will pair with

UAC   CUG   AGG   AUC

5 0
3 years ago
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