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Lana71 [14]
3 years ago
10

If two particles have equal charges and are placed near one another, how

Physics
1 answer:
navik [9.2K]3 years ago
5 0

Answer: C) The two particles will move away from each other

Explanation:

When two electrically charged bodies come closer, appears a force that attracts or repels them, depending on the sign of the charges of this two bodies.

This is stated by Coulomb's Law:

"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them"  

Mathematically this law is written as:  

F_{E}= K\frac{q_{1}.q_{2}}{d^{2}}  

Where K is a proportionality constant.  

Now, if q_{1} and q_{2} have the same sign charge (both positive or both negative), a repulsive force will act on these charges.

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2 years ago
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The more reactive an atom, the higher its potential energy. Which atom has the higher potential energy? Ne F Which of these stat
AleksAgata [21]

Fluorine (F) has higher potential energy as Neon (N) is a noble/inert gas.

Fluorine will lose another electron to gain stability.


7 0
3 years ago
provides one model for solving this problem. The maximum strength of the earth's magnetic field is about 6.9 x 10-5 T near the s
jeka57 [31]

Answer:

The minimum no. of turns is 3.126 \times 10^{5}

Explanation:

Given:

Magnetic field B = 6.9 \times 10^{-5} T

Frequency f = 84.5 Hz

Area of turn A = 0.021 m^{2}

Voltage V_{rms}  = 170 V

From the formula of induced emf,

V = NBA \omega

Where \omega = 2\pi f and V = \sqrt{2} V_{rms}

So number of turn is,

N = \frac{\sqrt{2} V_{rms} }{AB2\pi f }

N = \frac{\sqrt{2} \times 170 }{0.021 \times 6.9 \times 10^{-5} \times 6.28 \times 84.5 }

N = 3.126 \times 10^{5}

Therefore, the minimum no. of turns is 3.126 \times 10^{5}

4 0
3 years ago
DETERMINE THE LAUNCH ELEVATION AND MAXIMUM RANGE: The test vehicle should obtain a burnout velocity of 7200 m/s at 180 km altitu
fenix001 [56]

Answer:

Flight path angle= 15.12°, maximum range= 5.29× 10*6 km

Explanation:

u= 7200m/s, H= 180km= 180000m

Recall that

Maximum height, H= (u*2sin*2∆)/2g

180000= (7200×7200sin*2∆)/2×9.8

(18000×2×98)/7200×7200= sin*2∆

Sin∆= 0.2609

∆= 15.12°

Maximum range, R= u*2/g

(7200×7200)/9.8

= 5289795.92km

= 5.29× 10*6 km

8 0
3 years ago
It takes 4.186 J of energy to raise the temperature of lg of water by 1°C. How fast would a 2 g
mezya [45]

Answer:

1. D - 3.6 x 10^4 J

2. D - 0.04

3. A - 30.3 m/s

4. C - 3.67 x 10^8 J

5. A - 38.6 m

6. C - 7.07 m/s

7. B - 4.21 g

8. B - -6.56 J

9. A - 65 m/s

10. B - 116 Days

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3 years ago
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