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3 years ago

9

A pizza restaurant offers 21 different toppings. How many 5-topping pizzas can be created if each topping can be used only once?

2 answers:

TiliK225 [7]3 years ago

8 0

4.1 pizzas if thats an option

STatiana [176]3 years ago

6 0

4. 5 times 4 is 20. :)

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Need help with this. Show your steps so I could check my work and my answer.

andrezito [222]

Answer:

25

Step-by-step explanation:

The angle at C is 90 degrees, and BCD is a right triangle, so we can applythe Pythagorean theorem here -- 60²+m²=65², so 65²-60²=m²=625. The possible values for m are 25 and -25, and since m can't be negative, 25 is our answer as 25 is the square root of 625

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3 years ago

How many different lines of symmetry does a square have?

Sedaia [141]

Answer:

4

Step-by-step explanation:

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2 years ago

Two number cubes are tossed together; one is blue and the other is orange. What is the probability of getting an odd number on t

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5⇒(1,4),(3,2) where (orange,blue)

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3 years ago

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A rock climber averages 12 3/5 feet per minute. Write and solve an equation to find how many feet x the rock climber climbs in 3

sveticcg [70]

Answer:

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and the equation:

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Step-by-step explanation:

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2 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

so

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

5 0

3 years ago