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AysviL [449]
3 years ago
9

A particle moves along a straight line with a velocity V=(200s) mm/s, where s is in millimeters. Determine acceleration of the p

article at S = 2000mm.

Engineering
1 answer:
iragen [17]3 years ago
8 0

Answer:

200 mm/s²

Explanation:

See it in the pic

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Misha Larkins [42]

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small guitar with no strings?

Explanation:

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6 0
3 years ago
Who can use NIST resources?
sukhopar [10]

Answer:

Federal agencies

Explanation:

NIST (National Institute of Standards and Technology) also called between 1901 and 1988 National Bureau of Standards (NBS), it is an agency of the Technology Administration of the United States Department of Commerce. The mission of this institute is to promote innovation and industrial competition in the United States through advances in metrology, standards and technology in ways that improve economic stability and quality of life.

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7 0
3 years ago
Find the velocity and acceleration of box B when point A moves vertically 1 m/s and it is 5 m
Goshia [24]

Answer:

hshbdhehdjsbdjdissasoe

7 0
3 years ago
Suppose the measured background level is 5.1 mV. A signal of 20.7 mV is measured at a distance of 29 mm and 15.8 mV is measured
Paladinen [302]

Answer:  The normalized corrected value at 32.5 mm = 0.69 mV

Explanation:

Signal value V1 = 20.7 mV at

distance value = 29 mm and

V2 = 15.8 mV is measured at 32.5 mm. 

It is necessary, therefore, to subtract off this background level from the data to obtain a valid measurement

V1 = 20.7 - 5.1 = 15.6 mV

V2 = 15.8 - 5.1 = 10.7mV

The normalized corrected value at 32.5 mm will be

Vn = V2/V1 since V1 is the maximum value

Vn = 10.7/15.6 = 0.69 mV

3 0
3 years ago
Seawater has a specific density of 1.025. What is its specific volume in m^3/kg (to 3 significant figures of accuracy, tolerance
Svetradugi [14.3K]

Answer:

specific\ volume=0.00097\ m^3/kg

Explanation:

Given that

Specific gravity of sea water = 1.025

So density of sea water = 1.025 x 1000 kg/m^3

Density of sea water = 1025  kg/m^3

We know that

Density=\dfrac{mass}{Volume}   ---1

Specific volume

specific\ volume=\dfrac{Volume}{mass}    ---2

From equation 1 and 2

We can say that

specific\ volume=\dfrac{1}{density}\ m^3/kg

specific\ volume=\dfrac{1}{1025}\ m^3/kg

specific\ volume=0.00097\ m^3/kg

6 0
3 years ago
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