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Olenka [21]
2 years ago
13

Cuál es la resistencia de un foco que está conectado a una fuente de 20 v por el cuál pasa una intensidad de 20 mA

Physics
1 answer:
LUCKY_DIMON [66]2 years ago
7 0

Answer:

The resistance of the bulb is 1000 ohms.

Explanation:

What is the resistance of a bulb that is connected to a 20 v source through which a current of 20 mA passes

We have,

Voltage of the bulb is 20 V and the current passes is 20 mA.

It is required to find the resistance of the bulb. The relation between resistance, current and voltage is given by using Ohm's law as :

V =  IR

R is resistance

R=\dfrac{V}{I}\\\\R=\dfrac{20}{20\times 10^{-3}}\\\\R=1000\ \Omega

So, the resistance of the bulb is 1000 ohms.

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Answer:

\mathrm{d.\:Static,\: Sliding,\:Rolling}

Explanation:

Static friction occurs when an object initially starts at rest. When the surfaces of the materials touch, the microscopic unevenness interlock greatest with each other, causing the most friction out of the three.

During sliding friction, an object is already moving or in motion. The microscopic surfaces still interlock, but because the object is in motion, it has a momentum. Therefore, the magnitude of sliding friction is less than that of static friction.

Rolling friction occurs when an object rolls across some surface. Rather than surfaces interlocking, rolling friction is caused by the constant distortion of surfaces. As it rolls, the surfaces of the object are constantly wrapping and changing. This distortion causes the rolling friction. However, it is much less in magnitude when compared to static or sliding friction.

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Explanation:

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A bungee jumper with mass 65.0 kg jumps from a high bridge. After reaching his lowest point, he oscillates up and down, hitting
ololo11 [35]

Explanation:

It is given that,

Mass of a bungee jumper is 65 kg

The time period of the oscillation is 38 s, hitting a low point eight more times.It means its time period is

T=\dfrac{38}{8}\\\\T=4.75\ s

After many oscillations, he finally comes to rest 25.0 m below the level of the bridge.

For an oscillating object, the time period is given by :

T=2\pi \sqrt{\dfrac{m}{k}}

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k=\dfrac{4\pi ^2m}{T^2}\\\\k=\dfrac{4\pi ^2\times 65}{(4.75)^2}\\\\k=113.43\ N/m

When the cord is in air,

mg=kx

x = the extension in the cord

x=\dfrac{mg}{k}\\\\x=\dfrac{65\times 9.8}{113.6}\\\\x=5.6\ m

So, the unstretched length of the bungee cord is equal to 25 m - 5.6 m = 19.4 m

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