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Olenka [21]
3 years ago
13

Cuál es la resistencia de un foco que está conectado a una fuente de 20 v por el cuál pasa una intensidad de 20 mA

Physics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

The resistance of the bulb is 1000 ohms.

Explanation:

What is the resistance of a bulb that is connected to a 20 v source through which a current of 20 mA passes

We have,

Voltage of the bulb is 20 V and the current passes is 20 mA.

It is required to find the resistance of the bulb. The relation between resistance, current and voltage is given by using Ohm's law as :

V =  IR

R is resistance

R=\dfrac{V}{I}\\\\R=\dfrac{20}{20\times 10^{-3}}\\\\R=1000\ \Omega

So, the resistance of the bulb is 1000 ohms.

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Which property of a measurement is best estimated from the percent error? accuracy median precision range
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"Accuracy" would be the best option from the list regarding the property of a measurement that is best estimated from the percent error, since the higher the error is the lower the accuracy.


Explanation:

When taking scientific measurements, it's vital to be each correct and precise. Accuracy represents however shut a mensuration involves its true price. This can be vital as a result of unhealthy instrumentality, poor processing or human error will result in inaccurate results that aren't terribly getting ready to the reality.

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3 years ago
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A 42-kg crate rests on a horizontal floor, and a 52-kg person is standing on the crate. (a) determine the magnitude of the norma
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Hope this helps you.

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3 years ago
The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7
My name is Ann [436]

Answer:

0.28 m

Explanation:

The following data were obtained from the question:

Force (F) = 5×10¯⁶ N

Charge 1 (q₁) = 6.7×10¯⁹ C

Charge 2 (q₂) = 6.7×10¯⁹ C

Electrical constant (K) = 9×10⁹ Nm²C¯²

Distance apart (r) =?

Thus, the distance between the two charges can be obtained as follow:

F = Kq₁q₂/r²

5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²

5×10¯⁶ = 4.0401×10¯⁷ / r²

Cross multiply

5×10¯⁶ × r² = 4.0401×10¯⁷

Divide both side by 5×10¯⁶

r² = 4.0401×10¯⁷ / 5×10¯⁶

Take the square root of both side

r = √(4.0401×10¯⁷ / 5×10¯⁶)

r = 0.28 m

Therefore, the distance between the two charges is 0.28 m

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3 years ago
Why were phonograph records placed on the sides of the two voyager spacecraft launched in the 1970s?
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Answer:

The reason for phonograph installation is to provide information about humans to interstellar aliens.

Explanation:

Phonographs are archaic forms of gramophone which are able to record and reproduce sound.Phonographs were used in early days in voyagers to help transmit information about humans to nearby alien species in space.

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Answer:

C. Light rays are bent by the water in the glass

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That's the way science works and I learned about this before in class.

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