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kvv77 [185]
3 years ago
9

What type of nuclear decay is occurring between

Physics
1 answer:
Jlenok [28]3 years ago
8 0
Nuclear chosen would be the gamma because it’s the one choose to be radioactive more than others
You might be interested in
Help me with this review question please.
QveST [7]

Answer:

K E=( mv²)/2

=(60×3.5²)/2

=367.5J

6 0
3 years ago
It has been observed that electrical connectors manufactured by Jolt Electrical Supply Company last an average of 18.2 months an
Viktor [21]

Answer:

Jolt can expect to replace 160 units.

Explanation:

given data:

standard deviation 1.7

average lfe of connectors = 18.2 months

number of connectors = 5000

z(19) = \frac{(19-18.2)}{1.7}

z(19)  = 0.4706

P(x< 19) = P(z< 0.4706)

P(x< 19) = 0.6810   from z table

therefore 68.1% fails within 19 months.

hence 0.3190   {100-68.1} will fail during that period.

number of unit of Jolt that need to be replace, on average is  0.319*500 = 160 units.

7 0
3 years ago
Please help ASAP guys !!! Thanks
andreev551 [17]

Answer:

(a) gravitational potential energy converted to kinetic energy

(b) chemical energy is converted to light or heat energy

(c) mechanical energy is converted into kinetic energy

7 0
2 years ago
Add the vectors:
Anettt [7]

Vector 1 has components

x_1=(10\,\mathrm m)\cos20^\circ\approx9.40\,\mathrm m

y_1=(10\,\mathrm m)\sin20^\circ\approx3.42\,\mathrm m

and vector 2 has

x_2=(10\,\mathrm m)\cos80^\circ\approx1.74\,\mathrm m

y_2=(10\,\mathrm m)\sin80^\circ\approx9.85\,\mathrm m

Add these vectors to get the resultant, which has components

x_{\rm total}\approx11.133\,\mathrm m

y_{\rm total}\approx13.268\,\mathrm m

The magnitude of the resultant is

\sqrt{{x_{\rm total}}^2+{y_{\rm total}}^2}\approx17.321\,\mathrm m

with direction \theta such that

\tan\theta=\dfrac{y_{\rm total}}{x_{\rm total}}\implies\theta\approx50^\circ

or about 50º N of E.

8 0
3 years ago
A flatbed truck is carrying an 800-kg load of timber that is not tied down. The maximum friction force between the truck bed and
ycow [4]

Answer:

Acceleration a ≤ 3 m/s^2

the greatest acceleration that the truck can have without losing its load is 3 m/s^2

Explanation:

For the truck to accelerate without losing its load.

Acceleration force of truck must be less than or equal to the maximum friction force between the truck bed and the load.

Fa ≤ F(friction)

But;

Fa = mass × acceleration

Fa = ma

ma ≤ F(friction)

a ≤ (F(friction))/m ......1

Given;

Fa = mass × acceleration

Fa = ma

mass m = 800 kg

F(friction) = 2400 N

Substituting the given values into equation 1;

a ≤ F(friction)/m

a ≤ 2400N/800kg

a ≤ 3 m/s^2

the greatest acceleration that the truck can have without losing its load is 3 m/s^2

4 0
3 years ago
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