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Mrrafil [7]
3 years ago
8

Assume that all four H-R diagrams below represent a star in different stages of its life, after it starts to fuse hydrogen in it

s core. Rank the HR diagrams based on when each stage occurs, from first to last.
Physics
2 answers:
Mumz [18]3 years ago
3 0
The right answer for the question that is being asked and shown above is that: "1-4-3-2." (main sequence-->red giant-->supergiant-->white dwarf). Assume that all four H-R diagrams below represent a star in different stages of its life, after it starts to fuse hydrogen in its core.


Ilia_Sergeevich [38]3 years ago
3 0

Answer and explanation;

-The diagram at the left represents the Sun (or any other one-solar-mass star) as a hydrogen-burning main-sequence star, with spectral type G and one solar luminosity. The next diagram shows the Sun after it has exhausted its core hydrogen and left the main sequence, making it a sub-giant with energy generated by hydrogen burning in a shell around an inert helium core.

-The third diagram shows the Sun a little later; its energy source is still hydrogen shell burning, but at this point it has expanded in size so much that it is a red giant. The final diagram (far right) shows the white dwarf corpse of a one-solar-mass star; it is hot because it is the exposed core of the dead star, but dim because it is small in size.

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How does the viscosity of a liquid affect the definition of a liquid?
yaroslaw [1]

Viscosity is another type of bulk property defined as a liquid's resistance to flow. When the intermolecular forces of attraction are strong within a liquid, there is a larger viscosity. An example of this phenomenon is imagining a race between two liquids down a windshield.

4 0
3 years ago
Read 2 more answers
A fighter jet is launched from an aircraft carrier with the aid of its own engines and a steam-powered catapult. The thrust of i
kirza4 [7]

Answer:

2.5 x 10⁷ J

Explanation:

F = thrust of the engine = 2.3 x 10⁵ N

d = distance traveled = 87  m

Work done by the engine is given as

W = F d =  (2.3 x 10⁵) (87) = 200.1 x 10⁵ J

W' = Net work done

W'' = work done by catapult

KE₀ = initial kinetic energy = 0 J

KE = final kinetic energy = 4.5 x 10⁷ J

Net work done is given as

W' = KE - KE₀

W' = 4.5 x 10⁷ J

We know that

W' = W + W''

4.5 x 10⁷ = 2.001 x 10⁷ + W''

W'' = 2.5 x 10⁷ J

8 0
3 years ago
In part d, you saw that elements with even atomic numbers tend to be more abundant than neighboring elements with odd atomic num
jolli1 [7]
The atomic procedure clarifies why this is the situation is beginning from carbon ( the nuclear number is 6), the most widely recognized atomic responses include the combination of an extra helium core. I hope the answer will help you. 
8 0
3 years ago
Help plss .. Two bicyclists are accelerating forward in a straight line, and Biker 1 has less
castortr0y [4]

Explanation:

Remember Newton's Second Law.

F=ma

If the force acting on both bikers is the same, we can look at the relationship between acceleration and mass.

If Biker 1 has a mass of 10kg and Biker 2 has a mass of 20kg, and both are being acted upon by a force of 100 N, let's see what that looks like. 100 = 10*a_1 \rightarrow a_1 = 100/10 = 10

100 = 20 *a_2 \rightarrow a_2 = 100/20 = 5

So, given the same force, an object with GREATER mass will have less acceleration.

4 0
3 years ago
1.
Ivenika [448]

The ant's resultant velocity is 0.51 m/s at 78.7°

Since the ant is moving with a velocity of 0.1 m/s in the +x direction relative to the treadmill, and the treadmill is moving 0.5 m/s in the +y direction, the magnitude of the resultant velocity of the ant relative to the ground (since both directions are perpendicular) is thus

V = √(x² + y²)

= √[(0.1 m/s)² + (0.5 m/s)²]

= √[0.01 m²/s² + 0.25 m²/s²]

= √(0.26 m²/s²)

= 0.51 m/s.

The direction is Ф = tan⁻¹(y/x)

= tan⁻¹(0.5 m/s ÷ 0.1 m/s)

= tan⁻¹(5)

= 78.69°

≅ 78.7°

The ant's resultant velocity is 0.51 m/s at 78.7°

Learn more about resultant velocity here:

brainly.com/question/15093278

7 0
3 years ago
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