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Mrrafil [7]
3 years ago
8

Assume that all four H-R diagrams below represent a star in different stages of its life, after it starts to fuse hydrogen in it

s core. Rank the HR diagrams based on when each stage occurs, from first to last.
Physics
2 answers:
Mumz [18]3 years ago
3 0
The right answer for the question that is being asked and shown above is that: "1-4-3-2." (main sequence-->red giant-->supergiant-->white dwarf). Assume that all four H-R diagrams below represent a star in different stages of its life, after it starts to fuse hydrogen in its core.


Ilia_Sergeevich [38]3 years ago
3 0

Answer and explanation;

-The diagram at the left represents the Sun (or any other one-solar-mass star) as a hydrogen-burning main-sequence star, with spectral type G and one solar luminosity. The next diagram shows the Sun after it has exhausted its core hydrogen and left the main sequence, making it a sub-giant with energy generated by hydrogen burning in a shell around an inert helium core.

-The third diagram shows the Sun a little later; its energy source is still hydrogen shell burning, but at this point it has expanded in size so much that it is a red giant. The final diagram (far right) shows the white dwarf corpse of a one-solar-mass star; it is hot because it is the exposed core of the dead star, but dim because it is small in size.

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The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.420 with the floor. If
bonufazy [111]

Answer:

The distance is  s=  30.3 \ m

Explanation:

From the question we are told that

   The  coefficient of static friction is  \mu_s  =  0.42

    The  initial speed of the train is  u =  57 \  km /hr = 15.8 \ m/s

   

For the crate not to slide the friction force must be equal to the force acting on the train i.e

       -F_f  =  F

The negative sign shows that the two forces are acting in opposite direction

=>   mg  *  \mu_s  =  ma

=>   -g  *  \mu_s  = a

=>   a =  -9.8 *  0.420

=>   a =  -4.116 m/s^2

From equation of motion

  v^2  = u^2  +  2as

Here  v =  0 m/s since it came to a stop

=>   s=  \frac{v^2 - u^2 }{ 2 a}

 =>   s=  \frac{0 -(15.8)^2 }{ - 2 * 4.116}

=>     s=  30.3 \ m

7 0
3 years ago
An object moving in a constant velocity will always have a
jeka94

Answer:

constant velocity unless acted on my an opposite force

7 0
3 years ago
I need help witha worksheet over circuitsin physics could someone help??
garik1379 [7]
Yes u can help I need to see th worksheet to help tho
5 0
3 years ago
If the AMA of the inclined plane below is 2, calculate the IMA and efficiency. IMA = Efficiency =
wlad13 [49]

Answer:

IMA = 2.5 metres

EFFICIENCY = 80%

Explanation:

The AMA of a machine is referred to as the Actual Mechanical Advantage of a machine, calculated as the ratio of the output to the input force.

The Ideal Mechanical Advantage is the ratio of the input distance to the output distance.

From the diagram, the input distance which is also the distance moved by effort  = 5metres

The load distance (output distance) = 2 metres

IMA = INPUT DISTANCE / OUTPUT DISTANCE

IMA = 5metres / 2 metres = 2.5 meters

Efficiency is the ratio of AMA TO IMA

AMA = 2, IMA = 2.5

EFFICIENCY = AMA / IMA

EFFICIENCY = (2 / 2.5) × 100%= 0.8 × 100%

EFFICIENCY = 80%

5 0
3 years ago
Calculate the potential energy at the top of the giant drop if the car weights 1000 kg
bonufazy [111]
The gravitional potential energy, relative to the bottom of the giant drop, in joules, is (9800) times (the height of the drop in meters). That's the PE of the empty car only, not counting any hapless screaming souls who may be trapped in it at that moment.
6 0
3 years ago
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