No it is not. it is only found in animal products.
Answer:
1.117935:1
Explanation:
Since the wires are of the same material, they will have the same resistivity
.
The cross-sectional area of the of a wire is given by;
![A=\pi\frac{d^2}{4}................(1)](https://tex.z-dn.net/?f=A%3D%5Cpi%5Cfrac%7Bd%5E2%7D%7B4%7D................%281%29)
where d is the diameter of the wire.
Also, the relationship between resistance R, cross-sectional area A and length l of a wire is given as follows;
![\rho=\frac{RA}{l}..................(2)](https://tex.z-dn.net/?f=%5Crho%3D%5Cfrac%7BRA%7D%7Bl%7D..................%282%29)
Since the resistivity same for both wires, say wire 1 and wire 2, we can wreite the following;
![\frac{R_1A_1}{l_1}=\frac{R_2A_2}{l_2}..................(3)](https://tex.z-dn.net/?f=%5Cfrac%7BR_1A_1%7D%7Bl_1%7D%3D%5Cfrac%7BR_2A_2%7D%7Bl_2%7D..................%283%29)
Hence from eqaution (3), the ration of wire 1 to 2 is expressed as;
![\frac{R_1}{R_2}=\frac{l_1A_2}{l_2A_1}..................(4)](https://tex.z-dn.net/?f=%5Cfrac%7BR_1%7D%7BR_2%7D%3D%5Cfrac%7Bl_1A_2%7D%7Bl_2A_1%7D..................%284%29)
Given;
![l_1=1.35l_2](https://tex.z-dn.net/?f=l_1%3D1.35l_2)
![\frac{R_1}{R_2}=\frac{1.35l_2A_2}{l_2A_1}\\\frac{R_1}{R_2}=\frac{1.35A_2}{A_1}.............(5)](https://tex.z-dn.net/?f=%5Cfrac%7BR_1%7D%7BR_2%7D%3D%5Cfrac%7B1.35l_2A_2%7D%7Bl_2A_1%7D%5C%5C%5Cfrac%7BR_1%7D%7BR_2%7D%3D%5Cfrac%7B1.35A_2%7D%7BA_1%7D.............%285%29)
We then use equation (1) to fine the ratio of the area
to ![A_2](https://tex.z-dn.net/?f=A_2)
bearing in mind that ![d_1=0.91d_2](https://tex.z-dn.net/?f=d_1%3D0.91d_2)
This ratio gives 0.8281. Substituting this into equation (5), we get the following;
![\frac{R_1}{R_2}= 1.35*0.8281=1.117935](https://tex.z-dn.net/?f=%5Cfrac%7BR_1%7D%7BR_2%7D%3D%201.35%2A0.8281%3D1.117935)
The equation that relates distance, velocities, acceleration, and time is,
d = V₀t + 0.5gt²
where d is distance,
V₀ is the initial velocity,
t is time, and
g is the acceleration due to gravity (equal to 9.8 m/s²)
(1) Dropped rock,
(3 x 10² m ) = 0(t) + 0.5(9.8 m/s²)(t²)
The value of t from this equation is 24.73 s
(2) Thrown rock with V₀ = 26 m/s
(3 x 10² m) = (26)(t) + 0.5(9.8 m/s²)(t²)
The value of t from the equation is 5.61 s
The difference between the tim,
difference = 24.73 s - 5.61 s
difference = 19.12 s
<em>ANSWER: 19.12 s</em>
Answer:
Magnetic force, F = 0.24 N
Explanation:
It is given that,
Current flowing in the wire, I = 4 A
Length of the wire, L = 20 cm = 0.2 m
Magnetic field, B = 0.6 T
Angle between force and the magnetic field, θ = 30°. The magnetic force is given by :
![F=ILB\ sin\theta](https://tex.z-dn.net/?f=F%3DILB%5C%20sin%5Ctheta)
![F=4\ A\times 0.2\ m\times 0.6\ T\ sin(30)](https://tex.z-dn.net/?f=F%3D4%5C%20A%5Ctimes%200.2%5C%20m%5Ctimes%200.6%5C%20T%5C%20sin%2830%29)
F = 0.24 N
So, the force on the wire at an angle of 30° with respect to the field is 0.24 N. Hence, this is the required solution.