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wlad13 [49]
3 years ago
12

1. What does the horizontal axis ordinarily measure on an oscilloscope?

Physics
1 answer:
KonstantinChe [14]3 years ago
5 0

Answer:

1. OK the

1. The horizontal axis of a osclloscope is generally TIME axis.

2. given T =25 micro second

That is = 25E-6 s

Then We f = (1/T) .

So f = 1/(25 x 10^-6) = 40000 Hz =

40 KHz.

3. First Band will be Yellow

Second Band will be Violet

Third Band will be Red

And

Fourth Band will be Gold

Thus, the value of the resistance = (47 x 100)plus or minus 5%

= (4700 plus or minua5%) ohm

the range of the acceptable value of the resistance will now be

= 4465 ohm to 4935 ohm

(4)

The level provided by the wall outlet = 120 x √2 = 169.68 V

The √2 is because the multimeter measures RMS voltage rather than peak voltage and

RMS Voltage is = √2 x peak voltage

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A. Add it's Kinetic and Potential energies
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3 years ago
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When conduction electrons pass through a device with resistance, which describes their energy?
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Answer:

a) their potential energy increases.

Explanation:

Ohm's Law is

R= V/I

Where R= Resistance

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Clearly R and V are directly proportional i-e Potential energy increases with resistance.

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When the Earth is closest to the Sun, it is at:
ahrayia [7]

a). Perihelion . . . the point in Earth's orbit that's closest to the Sun.
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5 0
3 years ago
Which of these is an uneven rhythm movement? Question 5 options:
Musya8 [376]

Answer:

Sliding would be an uneven rhythm because Galloping and skipping has a constant flow of the same movement and same noise.

Explanation:

8 0
3 years ago
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A 2 kg rubber ball is thrown at a wall horizontally at 3 m/s, and bounces back the way it came at an equal speed. A 2 kg clay ba
Lyrx [107]

Answer:

THE RUBBER BALL

Explanation:

From the question we are told that

      The mass of the rubber ball is m_r   =  2 \ kg

      The  initial  speed of the rubber ball is  u =  3 \ m/s

      The final speed at which it bounces bank v  - 3 \ m/s

      The mass of the clay ball  is  m_c =  2  \ kg

       The  initial  speed of the clay  ball is u = 3 \ m/s

       The final speed of the clay ball is  v = 0 \  m/s

Generally Impulse is mathematically represented as

       I  =  \Delta p

where \Delta  p is the change in the linear momentum so  

       I  =  m(v-u)

For the rubber  is  

        I_r  =  2(-3 -3)

       I_r  = -12\ kg \cdot  m/s

=>     |I_r|  = 12\ kg \cdot  m/s

For the clay ball

       I_c  =  2(0-3)

        I_c =  -6 \ kg\cdot \ m/s

=>    | I_c| =  6 \ kg\cdot \ m/s

So from the above calculation the ball with the a higher magnitude of impulse is the rubber ball

       

8 0
4 years ago
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