All categories

3 years ago

1. What does the horizontal axis ordinarily measure on an oscilloscope?

Physics

1 answer:

KonstantinChe [14]3 years ago

5 0

Answer:

1. OK the

1. The horizontal axis of a osclloscope is generally TIME axis.

2. given T =25 micro second

That is = 25E-6 s

Then We f = (1/T) .

So f = 1/(25 x 10^-6) = 40000 Hz =

40 KHz.

3. First Band will be Yellow

Second Band will be Violet

Third Band will be Red

And

Fourth Band will be Gold

Thus, the value of the resistance = (47 x 100)plus or minus 5%

= (4700 plus or minua5%) ohm

the range of the acceptable value of the resistance will now be

= 4465 ohm to 4935 ohm

(4)

The level provided by the wall outlet = 120 x √2 = 169.68 V

The √2 is because the multimeter measures RMS voltage rather than peak voltage and

RMS Voltage is = √2 x peak voltage

You might be interested in

What would we do if we didn't have solar energy?

Anvisha [2.4K]

We would have to use wind or another source

8 0

3 years ago

Read 2 more answers

An electron, moving south, enters a magnetic field of certain strength. Because of this field the electron curves upward. What i

e-lub [12.9K]

Answer: The magnetic field points to the west.

Explanation:

If we take the plane as:

North = positive y-axis

East = positive x-axis.

We have that the electron is moving south, so the velocity of the electron can be written in vector form as:

V = (0, -v, 0)

Now, when the electron interacts with the magnetic field, the electron moves upwards.

We know that the interaction between an electron and a magnetic field is:

F = q*VxB

So we have that this force acts on the z-direction.

Now, to solve this we can use the righ hand rule.

First, we point wit our hand to the direction of the velocity (negative y-axis) now, we want that our thumb points up (the direction of the force) so the side where our palm faces is the direction of the field B.

But, remember that an electron has a negative charge, so the actual equation is:

F = -q*VxB

So the magnetic field actually points in the opposite direction of our palm, to the west.

Now, we can also solve it mathematically as:

F = (0, 0, f) = -q*(0, -v,0)x(a, b, c)

where B = (a, b, c) is the vector of the magnetic field.

(0, 0, f) = -q*(-v*b -0, -0 + 0, 0 -(- a*v)) = -q*(-v*b, 0, a*v)

then we have that b must be equal to zero, and that:

f = -q*a*v

and f is positive, then we have:

a = -(f/q*v)

then the vector of the magnetic field is:

B = (-(f/q*v), 0, 0)

so it points in the negative x-axis, that is the West, as we found earlier.

4 0

3 years ago

a ball is thrown horizontally from the roof of a building 45.0 m tall and lands 24.0 m from the base. What was the ball´s initia

Sliva [168]

ball drops 45m under g=10m/s/s

45=1/2x10xt^2 ... application of kinematic equaion from rest

90/10=t^2

t=3

24.0 m in 3 secs => 8m/s no air resistance

4 0

3 years ago

Show that rigid body rotation near the Galactic center is consistent with a spherically symmetric mass distribution of constant

irakobra [83]

To solve this problem we will use the concepts related to gravitational acceleration and centripetal acceleration. The equality between these two forces that maintains the balance will allow to determine how the rigid body is consistent with a spherically symmetric mass distribution of constant density. Let's start with the gravitational acceleration of the Star, which is

$a_g = \frac{GM}{R^2}$