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3 years ago

Object A has a higher temperature than Object B. Which statement must be ture?

Chemistry

2 answers:

harkovskaia [24]3 years ago

4 0

Object A hope this helps

God Bless

Zina [86]3 years ago

3 0

Answer: the answer is c

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Answer:

False

Explanation:

It is important to give exact measurements.

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4 years ago

Help asap i have to get a good grade on this

baherus [9]

I think The answer is 34.5l

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3 years ago

Geologists discover what seems to be a new, powdery substance, deep underground. When they analyze it it's found to contain, amo

german

Answer:

Explanation b:

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3 years ago

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so they are asking me to find the empirical formula for a compound that is 7.70% carbon and 92.3% chlorine. Can you show me step

Nikolay [14]

Answer:

Empirical formula is CCl₄

Explanation:

Given data:

Percentage of carbon = 7.70%

Percentage of chlorine = 92.3%

Empirical formula = ?

Solution:

Number of gram atoms of Cl = 92.3 / 35.5 = 2.6

Number of gram atoms of C = 7.70 / 12 = 0.64

Atomic ratio:

C : Cl

0.64/0.64 : 2.6/0.64

1 : 4

C : Cl = 1 : 4

Empirical formula is CCl₄.

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3 years ago

A 112 gram sample of an unknown metal was heated from 0.0C to 20.0C. The sample absorbed 1004 J of energy. What was the specific

worty [1.4K]

Answer:

The specific heat of the sample unknown metal is approximately 0.45 J/g °C.

General Formulas and Concepts:
Thermodynamics

Specific Heat Formula: $\displaystyle q = mc \triangle T$

m is mass (g)
c is specific heat capacity (J/g °C)
ΔT is the change in temperature

Explanation:

Step 1: Define

Identify variables.

m = 112 g

ΔT = 20.0 °C

q = 1004 J

Step 2: Solve for c

Substitute in variables [Specific Heat Formula]: $\displaystyle 1004 \ \text{J} = (112 \ \text{g})(c)(20.0 \ ^{\circ} \text{C})$
Simplify: $\displaystyle 1004 \ \text{J} = (2240 \ \text{g} \ ^\circ \text{C})c$
Isolate c: $\displaystyle c = 0.448214 \ \text{J} / \text{g} \ ^\circ \text{C}$
Round [Sig Figs]: $\displaystyle c \approx 0.45 \ \text{J} / \text{g} \ ^\circ \text{C}$

∴ specific heat capacity c is equal to around 0.45 J/g °C.

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Topic: AP Chemistry

Unit: Thermodynamics

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3 years ago