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3 years ago

Is it > greater than or < less than or = equal to? √6+5___6+√5

Mathematics

2 answers:

wlad13 [49]3 years ago

7 0

Answer:

√6+5 < 6+√5

Step-by-step explanation:

zhuklara [117]3 years ago

3 0

Answer:

√6+5<6+√5

Step-by-step explanation:

√6+5=7.44948974278

6+√5=8.2360679775

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Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

(a) Length of AB

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

(b) Are AB and CD congruent

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

(c) AB bisects CD or not?

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

(d) CD bisects AB or not?

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

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3 years ago

_____ terms are also expressions.

Lubov Fominskaja [6]

Answer:

Some.

Terms that include a number and a letter are expressions.

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3 years ago

Read 2 more answers

Simplify this problem

ikadub [295]

Answer:

$\boxed{ \frac{ \sqrt[3]{ {x}^{11} } }{4} }$

Step-by-step explanation:

$= > \frac{ {x}^{4} }{ \sqrt[3]{64x} } \\ \\ = > \frac{ {x}^{4} }{ {(64x)}^{ \frac{1}{3} } } \\ \\ = > \frac{ {x}^{4} }{ ({64}^{ \frac{1}{3} } )\times ({x}^{ \frac{1}{3} } )} \\ \\ = > \frac{ {x}^{4} }{ ({( {4}^{3} )}^{ \frac{1}{3} }) \times( {x}^{ \frac{1}{3} } )} \\ \\ = > \frac{ {x}^{4} }{ ({4}^{ \cancel{3} \times \frac{1}{ \cancel{3}} } ) \times( {x}^{ \frac{1}{3} } )} \\ \\ = > \frac{ {x}^{4} }{4 {x}^{ \frac{1}{3} } } \\ \\ = > \frac{ {x}^{4 - \frac{1}{3} } }{4} \\ \\ = > \frac{ {x}^{ \frac{12 - 1}{3} } }{4} \\ \\ = > \frac{ {x}^{ \frac{11}{3} } }{4} \\ \\ = > \frac{ \sqrt[3]{ {x}^{11} } }{4}$

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3 years ago

Last season, Alice’s soccer team won 6 games and lost 12 games. Her cousin Lucy’s team won 15 games and lost 18 games. Which tea

Naya [18.7K]

Answer: Alice's team

Step-by-step explanation: Add twelve and six you get 18; add 15 and 18 you get 33; now 18- 12= 6 so Alice won 6 games out of 18 so that ratio is 6:12 12-6=6; while Lucy's team's ratio is 15:18, 18- 15= 3. 3 is less than 6 so Alice's team had a higher ratio of wins to loses.

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3 years ago

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Determine a solution to system of linear inequalities graphed and justify your answer.

muminat

The last option. The lines graphed never touch so there is no solution

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2 years ago

Is it > greater than or < less than or = equal to? √6+5___6+√5​

Is it > greater than or < less than or = equal to? √6+5___6+√5