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Jlenok [28]
3 years ago
10

Why is boron and beryllium an exception to the octet rule

Chemistry
1 answer:
aliya0001 [1]3 years ago
4 0

Answer:

Explanation:

Beryllium especially, but Boron as well both exhibit metallic characteristics.

The outside ring of Beryllium contains 2 electrons. It would have to take on 6 electrons to have a ring of 8. The same statement can be made about Boron (except that it would need 5 electrons to make 8). It is easier for the atom to give up 2 or 3 than than to take on 5 or 6. It would not be easy to have a 5 or 6 minus charge on it.

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Active sites in enzymes are where substrates bind. Once they bind, a catalytic reaction occurs as a complex between substrate and enzyme is formed. Enzymes are termed as biocatalysts or simply catalysts since they speed up the catalytic reaction. After the reaction, they simply revert back to their original form, after having adjusted to fit with substrate. 
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3 years ago
Activity: A Ferris wheel with a diameter of 60.0 m is moving at a speed of 2.09 m/s. What is the centripetal
GarryVolchara [31]

Answer:

Centripetal acceleration of the wheel is 0.145\ m/s^2.

Explanation:

We have,

Diameter of a Ferris wheel is 60 m

Radius of the wheel is 30 m

Speed of the wheel is 2.09 m/s

It is required to find the centripetal  acceleration of the wheel. The formula of centripetal acceleration is given by :

a=\dfrac{v^2}{r}\\\\a=\dfrac{(2.09)^2}{30}\\\\a=0.145\ m/s^2

So, the centripetal acceleration of the wheel is 0.145\ m/s^2.

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3 years ago
PLS HELP IF YOU WANT A BRAINLIEST BEST ANSWER CHOICE GETS BRAINLIEST Which describes the two cells formed through mitosis?
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Answer:C

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3 years ago
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yulyashka [42]

Answer:

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Read 2 more answers
Calculate the Experimental Molar Volume in L/mol of the Hydrogen gas, H2, if the volume of H2 at STP is 52.8 mL and the mass of
lana66690 [7]

Answer:

The Experimental Molar Volume in L/mol of the Hydrogen gas=23.36L/mol

Explanation:

We are given that

Volume of H2 at STP=52.8mL

Mass of magnesium metal ,M(Mg)=0.055g

We have to find the Experimental Molar Volume in L/mol of the Hydrogen gas.

Molar mass of Mg=24.305 g/mol

Number of moles=\frac{given\;mass}{molar\;mass}

Using the formula

Number of moles of Mg=\frac{0.055}{24.305}moles

Number of moles of Mg=0.00226moles

Number of moles of Mg=Number of moles of H2

Number of moles of H2=0.00226moles

Molar volume of Hydrogen gas (H2)=\frac{volume\;at\;STP}{No\;of\;moles\;H_2}

Molar volume of Hydrogen gas (H2)=\frac{52.8}{0.00226}mL/mol

Molar volume of Hydrogen gas (H2)=\frac{52.8}{0.00226}\times 10^{-3}L/mol

1L=1000mL

Molar volume of Hydrogen gas (H2)=23.36L/mol

Hence, the Experimental Molar Volume in L/mol of the Hydrogen gas=23.36L/mol

6 0
3 years ago
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