Answer:
Mass of the planet = 1.48 × 10²⁵ Kg
Mass of the star = 5.09 × 10³⁰ kg
Explanation:
Given;
Diameter = 1.8 × 10⁷ m
Therefore,
Radius =
=
or
Radius of the planet = 0.9 × 10⁷ m
Rotation period = 22.3 hours
Radius of star = 2.2 × 10¹¹ m
Orbit period = 407 earth days = 407 × 24 × 60 × 60 seconds = 35164800 s
free-fall acceleration = 12.2 m/s²
Now,
we have the relation
g =
g is the free fall acceleration
G is the gravitational force constant
M is the mass of the planet
on substituting the respective values, we get
12.2 =
or
M = 1.48 × 10²⁵ Kg
From the Kepler's law we have
T² =
on substituting the respective values, we get
35164800² =
or
= 5.09 × 10³⁰ kg
Answer:
From left = 1.2L
From back = 0.9L
Explanation:
5 x = 3(L-X) + 2(2L-X)
X = 0.7L
Distance from left = 1.2L
7y = 2(L-X)+1(2L-x)
Y = 0.4L
Distance from back = 0.9L
I think it is A.. but then again im not sure
Answer:
a) 
b) 
Explanation:
Given:
- speed of rocket initially,

- top speed of rocket after acceleration,

- time taken to get to the top speed,

- final speed of the rocket,

- time taken to get to the final speed after reaching the top speed,

Now the acceleration:



Now as a fraction of gravity:


Now, the deceleration:


Now as a fraction of gravity:

