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Vlad [161]
3 years ago
8

Explain how forces of attraction and repulsion exist within an atom

Physics
2 answers:
Tamiku [17]3 years ago
8 0

Answer:

There are three kinds of forces within the atom:

      i) Electromagnetic force of attraction between the electrons and protons  

      ii) Electromagnetic force of repulsion between the protons or weak nuclear force  

      iii) Strong nuclear force between the electrons and protons

Explanation:

<u>Electromagnetic force of attraction:</u>

Electrons revolve in the orbits outside the nucleus. There exists an electromagnetic force of attraction between the electrons and protons. That’s why, electrons do not leave the atom.

<u>Weak nuclear force: </u>

It is an electromagnetic force of repulsion between the protons in the nucleus of the atoms.

<u>Strong nuclear force: </u>

This force is strongest from all the fundamentals forces and exists between the protons and neutrons in the nucleus of atom. This force overcomes the weak nuclear force and does not allow protons to stray away.  

Stels [109]3 years ago
7 0

Answer:

Oppositely charged particles attract each other, while like particles repel one another. Electrons are kept in the orbit around the nucleus by the electromagnetic force, because the nucleus in the center of the atom is positively charged and attracts the negatively charged electrons.

Explanation:

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Brainliest if correct Question 10 of 10
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A speedboat increases its speed from 14.5 m/s to 29.3 m/s in a distance of 172 m.
dalvyx [7]

Answer:

a. Acceleration, a = 1.88 m/s²

b. Time, t = 7.87 seconds.

Explanation:

Given the following data;

Initial velocity, U = 14.5m/s

Final velocity, V = 29.3m/s

Distance, S = 172m

a. To find the acceleration of the speedboat;

We would use the third equation of motion;

V² = U² + 2aS

Substituting into the formula

29.3² = 14.5² + 2a*172

858.49 = 210.25 + 344a

344a = 858.49 - 210.25

344a = 648.24

a = 648.24/344

Acceleration, a = 1.88 m/s²

b. To find the time;

We would use the first equation of motion;

V = U + at

29.3 = 14.5 + 1.88t

1.88t = 29.3 - 14.5

1.88t = 14.8

Time, t = 14.8/1.88

Time, t = 7.87 seconds.

6 0
3 years ago
An object moving with a speed of 35 m/a and has a kinetic energy of 1500j, what is the mass of the object
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Explanation:

Speed or velocity (V) = 35 m/s

Kinetic energy (K. E) = 1500 Joule

mass (m) = ?

We know

K.E = 1/2 * m * v²

1500 = 1/2 * m * 35²

1500 * 2 = 1225m

m = 3000 / 1225

m = 2.45 kg

The mass of the object is 2.45 kg

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