I would say yes, a magnetic reversal a threat to life on Earth. Base on articles, it is the end of the world if that happens. <span>Some people believe global cataclysm will occur when Earth's magnetic poles reverse. When north goes south, they say, the continents will lurch in one direction or the other, triggering massive earthquakes, rapid climate change and species extinctions.</span>
Answer:
<h3>
<em>2</em><em>4</em><em>7</em><em>9</em><em> </em><em>Newton</em></h3>
<em>Sol</em><em>ution</em><em>,</em>
<em>Mass</em><em>=</em><em>1</em><em>0</em><em>0</em><em> </em><em>kg</em>
<em>Accele</em><em>ration</em><em> </em><em>due</em><em> </em><em>to</em><em> </em><em>gravity</em><em>(</em><em>g</em><em>)</em><em>=</em><em>2</em><em>4</em><em>.</em><em>7</em><em>9</em><em> </em><em>m</em><em>/</em><em>s^</em><em>2</em>
<em>Now</em><em>,</em><em>.</em>
<em>
</em>
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>
Answer:
The charge on the dust particle is ![q_d = 6.94 *10^{-13} \ C](https://tex.z-dn.net/?f=q_d%20%20%3D%206.94%20%2A10%5E%7B-13%7D%20%5C%20%20C)
Explanation:
From the question we are told that
The length is ![l = 2.0 \ m](https://tex.z-dn.net/?f=l%20%3D%202.0%20%5C%20m)
The width is ![w = 4.0 \ m](https://tex.z-dn.net/?f=w%20%3D%204.0%20%5C%20m)
The charge is ![q = -10\mu C= -10*10^{-6} \ C](https://tex.z-dn.net/?f=q%20%3D%20%20-10%5Cmu%20C%3D%20-10%2A10%5E%7B-6%7D%20%5C%20C)
The mass suspended in mid-air is ![m_a = 5.0 \mu g = 5.0 *10^{-6} \ g = 5.0 *10^{-9} \ kg](https://tex.z-dn.net/?f=m_a%20%3D%20%205.0%20%5Cmu%20g%20%3D%20%205.0%20%2A10%5E%7B-6%7D%20%5C%20g%20%3D%20%205.0%20%2A10%5E%7B-9%7D%20%5C%20%20kg)
Generally the electric field on the carpet is mathematically represented as
![E = \frac{q}{ 2 * A * \epsilon _o}](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7Bq%7D%7B%202%20%2A%20%20A%20%20%2A%20%20%5Cepsilon%20_o%7D)
Where
is the permittivity of free space with value ![\epsilon_o = 8.85*10^{-12} \ \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2](https://tex.z-dn.net/?f=%5Cepsilon_o%20%3D%208.85%2A10%5E%7B-12%7D%20%20%5C%20%5C%20%20m%5E%7B-3%7D%20%5Ccdot%20kg%5E%7B-1%7D%5Ccdot%20%20s%5E4%20%5Ccdot%20A%5E2)
substituting values
![E = \frac{-10*10^{-6}}{ 2 * (2 * 4 ) * 8.85*10^{-12}}](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7B-10%2A10%5E%7B-6%7D%7D%7B%202%20%2A%20%20%282%20%2A%204%20%29%20%20%2A%20%208.85%2A10%5E%7B-12%7D%7D)
![E = -70621.5 \ N/C](https://tex.z-dn.net/?f=E%20%3D%20-70621.5%20%5C%20%20N%2FC)
Generally the electric force keeping the dust particle on the air equal to the force of gravity acting on the particles
![F__{E}} = F__{G}}](https://tex.z-dn.net/?f=F__%7BE%7D%7D%20%3D%20%20F__%7BG%7D%7D)
=> ![q_d * E = m * g](https://tex.z-dn.net/?f=q_d%20%2A%20%20E%20%20%3D%20%20m%20%2A%20g)
=> ![q_d = \frac{m * g}{E}](https://tex.z-dn.net/?f=q_d%20%20%3D%20%20%5Cfrac%7Bm%20%2A%20g%7D%7BE%7D)
=> ![q_d = \frac{5.0 *10^{-9} * 9.8}{70621.5}](https://tex.z-dn.net/?f=q_d%20%20%3D%20%20%5Cfrac%7B5.0%20%2A10%5E%7B-9%7D%20%2A%209.8%7D%7B70621.5%7D)
=> ![q_d = 6.94 *10^{-13} \ C](https://tex.z-dn.net/?f=q_d%20%20%3D%206.94%20%2A10%5E%7B-13%7D%20%5C%20%20C)
Answer:
Time taken = 8.25 second
Explanation:
Given:
Force = 4000 N
Force = ma
4,000 = (1100)(a)
Acceleration = 3.6363 m/s²
v = u + at
0 = 30 + (3.6363)t
Time taken = 8.25 second