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IrinaK [193]
3 years ago
10

Forrest drops a rock from a bridge to the water below. The rock entered the water at a speed of 19.6 m/s. How long did it take t

he pebble to reach the water from the bridge? [s=d/t]
Physics
1 answer:
Nataliya [291]3 years ago
4 0

Answer:

It took the rock 2 seconds to get to the water from the bridge.

Explanation:

Since Forrest drops the rock, it means its initial velocity is zero, and because it is freely falling under the influence of gravity, after time t it will gain a velocity v of

v = gt,

solving for t we get:

t = \dfrac{v}{g}.

Since in our case the velocity the rock gained was v= 19.6m/s and the acceleration due to gravity is g =9.8m/s^2, we have

t = \dfrac{19.6m/s}{9.8ms^{-2}}

\boxed{t =2s.}

Thus, the time took the rock to reach the water from the bridge was 2 seconds.

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A motorist drives north for 35.0 minutes at 85.0 kph. He then stops for 15.0 minutes. The motorist then drives 130.0 km in 2.0 h
o-na [289]

Answer:

A. 216.36 \frac{km}{h}

B. 96.56 \frac{km}{h}

Explanation:

Let s_{1} be the distance in first part.

s_{1} = velocity × time

s_{1} = 85 × \frac{35}{60}

s_{1} = 49.58 km

Let s_{2} be the distance in first part.

s_{2} = 130 km

Average velocity = \frac{Total displacement}{Total time}

When second leg of the trip is

A. Toward north

Average velocity = \frac{[tex] s_{1} + s_{2}}{Total time}  [/tex]

Average velocity = \frac{130+49.58}{0.25+0.58}

Average velocity =216.36 \frac{km}{h}

B. Toward south

Average velocity = \frac{[tex] s_{1} - s_{2}}{Total time}  [/tex]

Average velocity = \frac{130-49.58}{0.25+0.58}

Average velocity =96.56 \frac{km}{h}


3 0
3 years ago
Which does a reference point provide? Select two options. a position from which to measure future distance a set of standard uni
In-s [12.5K]

Answer:

hope this helps you :)

Explanation:

An object is in motion if its position changes relative to another object. To decide if you are moving, you can use your chair as a reference point. A reference point is a place or object used for comparison to determine if something is in motion.

4 0
4 years ago
A pendulum has 895 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o
LuckyWell [14K]

Newton's law of conservation states that energy of an isolated system  remains a constant. It can neither be created nor destroyed but can be transformed  from one form to the other.

Implying the above law of conservation of energy in the case of pendulum we can conclude that at the bottom of the swing the entire potential energy gets converted to kinetic energy. Also the potential energy is zero at this point.

Mathematically also potential energy is represented as

Potential energy= mgh

Where m is the mass of the pendulum.

g is the acceleration due to gravity

h is the height from the bottom z the ground.

At the bottom of the swing,the height is zero, hence the potential energy is also zero.

The kinetic energy is represented mathematically as

Kinetic energy= 1/2 mv^2

Where m is the mass of the pendulum

v is the velocity of the pendulum

At the bottom the pendulum has the maximum velocity. Hence the kinetic energy is maximum at the bottom.

Also as it has been mentioned energy can neither be created nor destroyed hence the entire potential energy is converted to kinetic energy at the bottom and would be equivalent to 895 J.

7 0
4 years ago
If two cars have the same velocity do they have the same acceleration
Allisa [31]
No, if it takes less time, the acceleration is greater.

Hope this helps!
3 0
3 years ago
In an alcohol-in-glass thermometer, the alcohol column has length 12.66 cm at 0.0 ∘C and length 22.49 cm at 100.0 ∘C. Part A Wha
anygoal [31]

Answer:

62.1566632757\ ^{\circ}C

15.9715157681\ ^{\circ}C

Explanation:

\Delta T = Change in termperature

\Delta L = Change in length

We have the relation

\dfrac{\Delta L}{\Delta T}=\dfrac{22.49-12.66}{100-0}=\dfrac{18.77-12.66}{t-0}\\\Rightarrow t=\dfrac{18.77-12.66}{0.0983}\\\Rightarrow t=62.1566632757\ ^{\circ}C

The temperature is 62.1566632757\ ^{\circ}C

\dfrac{\Delta L}{\Delta T}=\dfrac{22.49-12.66}{100-0}=\dfrac{14.23-12.66}{t-0}\\\Rightarrow t=\dfrac{14.23-12.66}{0.0983}\\\Rightarrow t=15.9715157681\ ^{\circ}C

The temperature is 15.9715157681\ ^{\circ}C

8 0
3 years ago
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