1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
torisob [31]
3 years ago
9

What do you think causes the differences in the properties of oxygen gas (O2) and ozone (O3)? the space between the atoms the ra

tio of atoms in the molecules cannot tell the number of oxygen atoms
Engineering
1 answer:
Ivahew [28]3 years ago
4 0

Answer:

Oxygen is an important part of the atmosphere and is necessary to sustain terrestrial life. Because it comprises most of the mass in water, it also comprises most of the mass of living organisms. All major classes of structural molecules in living organisms, such as proteins, carbohydrates, and fats, contain oxygen, as do the major inorganic compounds that comprise animal shells, teeth, and bone. Elemental oxygen (O2) is produced by cyanobacteria, algae, and plants through the process of photosynthesis, and is used in cellular respiration by most living organisms on earth. Oxygen is toxic to obligate anaerobic organisms (organisms which need a lack of oxygen for survival), which were the dominant form of early life on Earth, until O2 began to accumulate in the atmosphere.

Explanation:

You might be interested in
A simple ideal Rankine cycle with water as the working fluid operates between the pressure limits of 4 MPa in the boiler and 20
viktelen [127]

Answer:

a) 69,630KW

b) 203 KW

Explanation:

The data obtained from Tables A-4, A-5 and A-6 is as follows:

h_{1} = h_{f,@20KPa} = 251.42 KJ/kg\\v_{1} = v_{f,@20KPa} = 0.001017 KJ/kgK\\\\w_{p,in} = v_{1} * (P_{2} - P_{1})\\w_{p,in} = (0.001017)*(4000-20)\\\\w_{p,in} = 4.05 KJ/kg\\\\h_{2} = h_{1} - w_{p,in} \\h_{2} = 251.42 + 4.05\\\\h_{2}  =  255.47KJ/kg\\\\P_{3} = 4000KPa\\T_{3} = 700 C\\s_{3} = 7.6214 KJ/kgK\\\\h_{3} = 3906.3 KJ/kg\\\\P_{4} = 20 KPa\\s_{3} = s_{4} = 7.6214KJ/kgK\\s_{f} = 0.8320 KJ/kgK\\s_{fg} = 7.0752 KJ/kgK\\\\

x_{4} = \frac{s_{4} - s_{f} }{s_{fg} }  \\\\x_{4} = \frac{7.6214-0.8320}{7.0752} = 0.9596\\\\h_{f} = 251.42KJ/kg \\h_{fg} = 2357.5KJ/kg \\\\h_{4} = h_{f} + x_{4}*h_{fg} = 251.42 + 0.9596*2357.5 = 2513.7KJ/kg\\\\

The power produced and consumed by turbine and pump respectively are:

W_{T,out} = flow(m) *(h_{3} - h_{4}) \\W_{T,out} = 50 *(3906.3-2513.7)\\\\W_{T,out} = 69,630 KW\\\\W_{p,in} = flow(m) *w_{p,in} = 50*4.05 = 203 KW

7 0
3 years ago
The volume of microbial culture is observed to increase according to the formula
saw5 [17]

The expression of V(m³)=e^(t(s)) to make V in in³ and t in minutes is;

V(in³) = (¹/₆₁₀₂₄)ae^{\frac{1}{60}bt(h)

We are given that;

Volume of microbial culture is observed to increase according to the formula;

V = e^(t)

where;

t is in seconds

V is in m³

We want to now express V in in³ and t in minutes.

Now, from conversions;

1 m³ = 61024 in³

Also; 1 second = 1/60 minutes

according to formula for exponential decay, we know that;

V = ae^(bt)

Thus, we have;

61024V = ae^(¹/₆₀b(t(h))

V(in³) = (¹/₆₁₀₂₄)ae^{\frac{1}{60}bt(h)

Read more about subject of formula at; brainly.com/question/790938

3 0
2 years ago
Two Technicians are discussing shock absorbers. Technician A says most shock absorbers help support vehicle weight. Technician B
yKpoI14uk [10]

Answer:

Both Technician A and B

Explanation:

In a vehicle suspension system, a shock absorber has the functions such as; limiting the movement of the vehicle, stabilizing the ride, stabilizing the tires of the vehicle, minimizing wear and tear in the vehicle and decreasing the overall suspension tear.  Some of the ways of maintaining shock absorbers is to inspect the strut for leaks.Shock oil sometimes leaks to cover the seals with a transparent liquid.

6 0
3 years ago
Solve using Matlab the problems:
Firlakuza [10]

Answer:

Explanation:

% Clears variables and screen

clear; clc

% Asks user for input

n = input('Total number of objects: ');

r = input('Size of subgroup: ');

% Computes and displays permutation according to basic formulas

p = 1;

for i = n - r + 1 : n

   p = p*i;

end

str1 = [num2str(p) ' permutations'];

disp(str1)

% Computes and displays combinations according to basic formulas

str2 = [num2str(p/factorial(r)) ' combinations'];

disp(str2)

=================================================================================

Example: check

How many permutations and combinations can be made of the 15 alphabets, taking four at a time?

The answer is:

32760 permutations

1365 combinations

==================================================================================

7 0
2 years ago
In some synchronizer applications, the clock frequency f is substituted for the parameter a in metastability MTBF calculations,
Contact [7]

Answer:

Please see the attached file for the complete answer.

Explanation:

Download pdf
4 0
3 years ago
Other questions:
  • Which term defines the amount of mechanical work an engine can do per unit of heat energy it uses?
    5·1 answer
  • Material with hardness of 220 Vickers is harder than material with a hardness of 180 Vickers. a)-True b)- False
    8·1 answer
  • Find the pressure exerted by the water bed on the floor when the bed rests in its normal position. Assume the entire lower surfa
    12·1 answer
  • Is air conditioner a refrigerator?
    10·1 answer
  • Who is the best musician in Nigeria<br>​
    11·2 answers
  • 10. To cut 1/4" (6 mm) thick mild steel at a rate of 40 inches per minute, the current would be set to
    7·1 answer
  • All of the following are categories for clutch covers except
    11·1 answer
  • Draw the sequence of BSTs that results when you insert the keys E, A, S, Y, Q, U, E, S, T, I, O, N, in that order into an initia
    10·1 answer
  • Good Morning. Can you help me on this question please?
    5·2 answers
  • This might count as engineering, I'm not sure as this is IT
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!