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3 years ago

Narrow belts of high-speed winds that blow in the upper troposphere and lower stratosphere are known as

Physics

1 answer:

Drupady [299]3 years ago

3 0

<h2>Jet Stream</h2>

Explanation:

Jet streams are the winds that flow in the upper levels of the atmosphere.
These are relatively narrow bands of strong wind.
These high-speed winds blow from west to east in jet streams.
Sometimes, the flow of wind shifts from north to south.
Jet streams follow the boundaries between hot and cold air.

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A car slows from 27 m/s to 5 m/s with a constant acceleration for 6.87 s. What is the car’s acceleration?

Kobotan [32]

In this case, the movement is uniformly delayed (the final rapidity is less than the initial rapidity), therefore, the value of the acceleration will be negative.

1. The following equation is used:

a = (Vf-Vo)/ t

a: acceleration (m/s2)

Vf: final rapidity (m/s)

Vo: initial rapidity (m/s)

t: time (s)

2. Substituting the values in the equation:

a = (5 m/s- 27 m/s)/6.87 s

3. The car's acceleration is:

a= -3.20 m/ s<span>^2</span>

5 0

3 years ago

A diver comes off a board with arms straight up and legs straight down, giving her a moment of inertia about her rotation axis o

mihalych1998 [28]

Answer:

θ₁ = 0.5 revolution

Explanation:

We will use the conservation of angular momentum as follows:

$L_1=L_2\\I_1\omega_1=I_2\omega_2$

where,

I₁ = initial moment of inertia = 18 kg.m²

I₂ = Final moment of inertia = 3.6 kg.m²

ω₁ = initial angular velocity = ?

ω₂ = Final Angular velocity = $\frac{\theta_2}{t_2} = \frac{2\ rev}{1.2\ s}$ = 1.67 rev/s

Therefore,

$(18\ kg.m^2)\omega_1 = (3.6\ kg.m^2)(1.67\ rev/s)\\\\\omega_1 = \frac{(3.6\ kg.m^2)(1.67\ rev/s)}{(18\ kg.m^2)}\\\\\omega_1 = \frac{\theta_1}{t_1} = 0.333\ rev/s\\\\\theta_1 = (0.333\ rev/s)t_1$

where,

θ₁ = revolutions if she had not tucked at all = ?

t₁ = time = 1.5 s

Therefore,

$\theta_1 = (0.333\ rev/s)(1.5\ s)\\$

<u>θ₁ = 0.5 revolution</u>

4 0

3 years ago

I need help with 23 please.

Ne4ueva [31]

The answer is c.

hope this helps! :)

8 0

3 years ago

If you lift a 16 kg child from the floor to her bed, which is 1 meter high, how much have you increased her potential energy.

Amanda [17]

GPE=mgh
GPE=16•9.8•1

6 0

3 years ago

6) How much current flows through a 100W light bulb that is plugged into a 120 V outlet?

sineoko [7]

Answer:

8.3A

Explanation:

1000 =120I

I =1000/120=8.3A

4 0

3 years ago