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slavikrds [6]
3 years ago
6

Narrow belts of high-speed winds that blow in the upper troposphere and lower stratosphere are known as

Physics
1 answer:
Drupady [299]3 years ago
3 0
<h2>Jet Stream</h2>

Explanation:

  • Jet streams are the winds that flow in the upper levels of the atmosphere.
  • These are relatively narrow bands of strong wind.
  • These high-speed winds blow from west to east in jet streams.
  • Sometimes, the flow of wind shifts from north to south.
  • Jet streams follow the boundaries between hot and cold air.
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Define s.i unit of force explanation
kvv77 [185]
<h3><u>Answer</u> :</h3>

◈ As per newton's second law of motion, Force is defined as the product of mass and acceleration.

Mathematically,

\dag\:\boxed{\bf{\purple{F=ma}}}

Unit of mass : kg

Unit of acceleration : m/s²

Therefore,

Unit of force ➠ <u>kg m/s²</u>

SI unit : <u>N (newton)</u> or <u>kg m/s²</u>

3 0
4 years ago
A condition that affects the ability to sleep or the quality of sleep is referred to as a __________.
Anit [1.1K]
The answer is B) Sleep disorder.  Notice that is says, "A condition that affects the ability to sleep or quaility of sleep." Meaning how much sleep you get. Also known as sleep disorder. Answer is B. Hope that helps :)
7 0
3 years ago
Read 2 more answers
Which one of these birds is an experimental population
kkurt [141]

Answer Whooping Crane

An experimental population is a geologically depicted gathering of reintroduced plants or creatures that is segregated from other existing populaces of the species. It is done to protect the endangered species from getting extinct. Whooping crane is also one of those birds which were endangered and experimental population technique was used.

4 0
3 years ago
Read 2 more answers
Two large, parallel, nonconducting sheets of positive charge face each other. What is at points (a) to the left of the sheets, (
alexira [117]

Answer:

a)The electric Field will be zero at the point between the sheets

b)E_1=\dfrac{\sigma}{\epsilon_0}

c)E_2=\dfrac{\sigma}{\epsilon_0}

Explanation:

Let \sigma be the surface charge density of the of the non conducting parallel sheet.Let consider a Gaussian surface in the form of of cylinder such that its cross-sectional is A . Then there will be flux only due to cross sectional area as the curved sectional is perpendicular to the the electric field  so the Electric Flux due to it is zero.

Now using Gauss law we have, E be the electric Field at the distance r from the sheet then

E\times 2A=\dfrac{\sigma A}{\epsilon_0}\\E=\dfrac{\sigma}{2\epsilon_0}

The Field will be away from the sheet and perpendicular to it.

a) The Electric Field between them

E_1=\dfrac{\sigma}{2\epsilon_0}-\dfrac{\sigma}{2\epsilon_0}\\=0

b)The Electric Field to the right of the sheets

E_1=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

c)The Electric Field to the left of the sheets

E_2=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

3 0
3 years ago
A system dissipates 12 J of heat into the surroundings; meanwhile, 28 J of work is done on the system. What is the change of the
timurjin [86]

Answer:

option C

Explanation:

given,

energy dissipated by the system to the surrounding = 12 J

Work done on the system = 28 J

change in internal energy of the system

Δ U = Q - W

system losses energy = - 12 J

work done = -28 J

Δ U = Q - W

Δ U = -12 -(-28)

Δ U = 16 J

hence, the correct answer is option C

6 0
3 years ago
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