The rest energy of a particle is
where
is the rest mass of the particle and c is the speed of light.
The total energy of a relativistic particle is
where v is the speed of the particle.
We want the total energy of the particle to be twice its rest energy, so that
which means:
From which we find the ratio between the speed of the particle v and the speed of light c:
So, the particle should travel at 0.87c in order to have its total energy equal to twice its rest energy.
Number 13 is D the heart has 4 chambers and pumps blood to the arteries and number 14 us C
Answer: The correct answer is Image B.
Explanation: For an object to accelerate, there should be unbalanced forces present. An object will move in the direction of net force.
Balanced forces are defined as the forces acting on the same object which are equal in magnitude but act in opposite direction. The net forces are 0.
Unbalanced forces are defined as the forces acting on the same object which are unequal in magnitude. The net force is non-zero.
For the given images:
Image A: This box will accelerate easily because the net force is non-zero and is moving in right direction.
Image B: This box will not accelerate because the net force is zero as all the forces are balancing one another. Hence, the object will stay at rest.
Image C: This box will accelerate easily because the net force is non-zero and is acting in between the normal and applied force.
Image D: This box will accelerate easily because the net force is non-zero and is moving in right direction.
Hence, the correct option is Image B.
Given Information:
Current in loop = I = 62 A
Magnitude of magnetic field = B = 1.20x10⁻⁴ T
Required Information:
Radius of the circular loop = r = ?
Answer:
Radius of the circular loop = 0.324 m
Explanation:
In a circular loop of wire with radius r and carrying a current I induces a magnetic field B which is given by
B = μ₀I/2r
Please note that for an infinitely straight long wire we use 2πr whereas for circular loop we use 2r
Where μ₀= 4πx10⁻⁷ is the permeability of free space
Re-arranging the equation yields
r = μ₀I/2B
r = 4πx10⁻⁷*62/2*1.20x10⁻⁴
r = 0.324 m
Therefore, the radius of this circular loop is 0.324 m
Answer:
4°
Explanation:
Given,
chord in the airstream, c = 2 m
speed, v = 50 m/s
lift per unit span = 1353 N/m
density of air, ρ = 1.225 kg/m³
Lift,
From the plot of c_L and angle of attack
Angle of attack is equal to 4°
