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fenix001 [56]
2 years ago
10

Water flowing from a waterfall before it hits the pond below?

Physics
1 answer:
anastassius [24]2 years ago
8 0

Answer:

Kinetic Energy

Explanation:

Ang prinsipyo ay nagsasaad na ang enerhiya ay hindi maaaring malikha o masira, ngunit maaari lamang ma-convert mula sa isang anyo patungo sa isa pa. Ang tubig sa tuktok ng napakataas na talon ay nagtataglay ng gravitational potential energy. Habang bumabagsak ang tubig, ang enerhiya na ito ay na-convert sa kinetic energy, na nagreresulta sa isang daloy sa isang mataas na bilis.

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A ray of light traveling in air is incident on the surface of a block of clear ice (of index 1.309) at an angle of 25.5 ◦ with t
sergij07 [2.7K]

Answer: 135.29\º

The figure attached will be helpful to understand the solution.

Here we see two cases, reflection and refraction of light.

According to the laws of reflection:

1. The incident ray, the reflected ray and the normal are in the same plane.

2. The angle of incidence is equal to the angle of reflection.

<u>*Note the normal is perpendicular to the plane, with a 90\º angle with the surface</u>

And this can be visualized in the figure, where the angle {\theta}_{1} with which the incident ray hits the surface is equal to the angle with which this same ray is reflected.

On the other hand we have Refraction, a phenomenon in which  the light bends or changes its direction when passing through a medium with a refractive index different from the other medium.

In this context, the Refractive index is a number that describes how fast light propagates through a medium or material.  

According to Snell’s Law:  

n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2})     (1)  

Where:  

n_{1}=1 is the first medium refractive index  (the air)

n_{2}=1.309 is the second medium refractive index  (the ice)

\theta_{1}=25.5\º is the angle of the incident ray  

\theta_{2} is the angle of the refracted ray  

Now, firstly we have to find \theta_{2} and then, by geometry, find \alpha and \beta which sum the <u>angle between the reflected and the refracted light</u>.

Finding \theta_{2} from (1):

(1)sin(25.5\º)=(1.309)sin(\theta_{2})    

sin(\theta_{2})=0.328

\theta_{2}=arcsin(0.328)

\theta_{2}=19.201\º   (2)

Remembering that the Normal makes  a 90\º angle with the surface, we can say:

90\º=\theta_{1}+\beta    (3)

Finding \beta:

\beta=90\º-25.5\º=64.5\º    (4)

Doing the same with  \theta_{2} and  \alpha}:

90\º=\theta_{2}+\alpha    (5)

Finding \alpha:

\alpha=90\º-19.201\º=70.79\º    (6)

Adding both angles (4) and (6):

\alpha+\beta=70.79\º+64.5\º    (7)

\alpha+\beta=135.29\º>>>This is the angle between the reflected and the refracted light.

5 0
3 years ago
Which characteristic of water allows its molecules to form hydrogen bonds? The water molecule is polar. Water has a low specific
Fittoniya [83]
Definitely the first: the water molecule is polar. :)
5 0
3 years ago
Read 2 more answers
Como anticipan la caída del proyectil, con movimiento parabólico para que el misil no haga daño
Elena L [17]

Answer:

Conociendo la velocidad inicial del proyectil y el angulo de lanzamiento con respecto ala horizontal.

Explanation:

Para poder anticipar la caída del proyectil es importante conocer la velocidad inicial del proyectil y el angulo de disparo del proyectil con respecto a la horizontal.

A continuación se presenta un diagrama o esquema donde se pueden ver estas variables y se explicaran a la brevedad:

Para poder encontrar el rango que es la máxima distancia horizontal recorrida por el proyectil debemos utilizar la siguiente ecuación:

x=(v_{o})_{x} *t\\where:\\(v_{o})_{x} = velocidad inicial  x-component [m/s]\\t= time [s]

Para poder encontrar el tiempo debemos utilizar la siguiente ecuación:

y=(v_{y} )_{o}*t-0.5*g*t^{2}  \\donde:\\(v_{y} )_{o}= velocidad inicial componente y [m/s]\\g = gravity = 9.81 [m/s^2]\\t = time [s]

En la anterior ecuación, igualamos y = 0, ya que cuando el proyectil cae al suelo la distancia vertical es cero. De esta manera podemos encontrar el tiempo t, ya que conocemos la velocidad inicial del proyectil en la componente y.

Seguidamente reemplazamos t en la primera ecuacion y encontramos la distancia x o el rango.

8 0
3 years ago
Classify Cd2+ Mn2+ Kr Zr as Paramagnetic or diamagnetic
jeka57 [31]
We classify the elements as follows:

<span>Cd2+ = Diamagnetic
Mn2+ = Paramagnetic
Kr = Diamagnetic
Zr = Paramagnetic

Diamagnetic when </span><span>all electrons are paired which means that in an orbital an electron spins clockwise and another spins anticlockwise while paramagnetic is the opposite.</span><span>


</span>
5 0
3 years ago
The base si unit for electric is the
nevsk [136]

The basic SI unit that has anything to do with electricity is the unit
of electric charge ... the Coulomb.

Every other unit connected with electricity is a combination of the
Coulomb and the other basic SI units ...kilogram for mass, the meter
for length, and the second for time.


6 0
3 years ago
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