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Cloud [144]
3 years ago
7

Cedrick & Astrid titrated a 10.00 mL aliquot of grapefruit juice with a 0.171 M NaOH solution to the end point. They calcula

ted that there was 0.1698 g of citric acid present in the juice sample. What is the amount mg of citric acid present per mL of juice?
Chemistry
1 answer:
Strike441 [17]3 years ago
5 0

Answer:

17 mg/ml.

Explanation:

Since NaOH was titrated against Citric acid in the grape fruit, therefore

Converting g to mg,

0.1698 g * 1000 mg/1 g

= 169.8 mg

Volume of grapefruit juice = 10 ml

Mass of Citric acid in ml of juice = 169.8/10

= 17 mg/ml.

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Is a tooth made out of matter or not matter?
LenKa [72]

Human teeth are made up of four different types of tissues.

4 0
2 years ago
Picric acid has been used in the leather industry and in etching copper. However, its laboratory use has been restricted because
olchik [2.2K]

Answer:

0.3023 M

Explanation:

Let Picric acid = H_{picric}

So,  H_{picric}     +       H_2}O          ⇄      H_3}O^+     +     Picric^-

The ICE table can be given as:

                          H_{picric}     +       H_2}O          ⇄      H_3}O^+     +     Picric^-

Initial:                0.52                                               0                  0

Change:             - x                                                 + x                 + x

Equilibrium:      0.52 - x                                        + x                 + x

Given that;

acid dissociation constant  (K_a) = 0.42

K_a = \frac{[H_3O^+][Picric^-]}{H_{picric}}

0.42 = \frac{[x][x]}{0.52-x}}

0.42 = \frac{[x]^2}{0.52-x}}

0.42(0.52-x) = x²

0.2184 - 0.42x = x²

x²  + 0.42x - 0.2184 = 0                   -------------------- (quadratic equation)

Using the quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}    ;     ( where +/-  represent ± )

= \frac{-0.42+/-\sqrt{(0.42)^2-4(1)(-0.2184)} }{2*1}

= \frac{-0.42+/-\sqrt {0.1764+0.8736} }{2}

= \frac{-0.42+\sqrt {1.0496} }{2}     OR   \frac{-0.42-\sqrt {1.0496} }{2}

= \frac{-0.42+1.0245}{2}       OR    \frac{-0.42-1.0245}{2}

= \frac{0.6045}{2}                 OR    -\frac{1.4445}{2}

= 0.30225          OR     - 0.72225

So, we go by the +ve integer that says:

x =  0.30225

x = [ H_3}O^+ ] = [   Picric^- ] =  0.3023  M

∴  the value of  [H3O+] for an 0.52 M solution of picric acid  = 0.3023 M     (to 4 decimal places).

6 0
3 years ago
Which statement best relates the strength and concentration of a base? At high enough concentrations, a weak base becomes strong
Lorico [155]

Answer: Option (b) is the correct answer.

Explanation:

When there are more number of hydroxide ions in a solution then there will be high concentration of OH^{-} or hydroxide ions. As a result, more will be the strength of base in that particular solution.

A base is strong when it readily dissociate into its ions in the solution. When a base is strong, then it does not matter at what concentration it is dissolved in the solution because despite of its low concentration it will remain a strong base.

Thus, we can conclude that out of the given options, the statement even at low concentrations, a strong base is strong best relates the strength and concentration of a base.


6 0
3 years ago
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Fill in the blank: After a chemical reaction, the atoms of the reactant _____ to form new products.
Wewaii [24]
The atoms of the reactant rearrange to form new products.
8 0
3 years ago
write the equation that matches the description one atom of zinc reacts with one atom of sulfur to yield one molecule of zinc su
Elis [28]

Answer: Zn + S —> ZnS

Explanation:

3 0
3 years ago
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