Answer:
v_average =0
Explanation:
In kinematics the average speed defined with the distance interval traveled in a given time interval
V = Δx /Δt
in this case the tennis ball travels a distance h to the highest point and a distance h from the highest point to the floor, so the distance you travel zero
Dy = h -h = 0
therefore the average speed should be zero
v_average =0
The biggest one in the water
Answer: B=1.92nT
Explanation:This question uses the Biot-Savart law: the law is an equation that describes the magnetic field created by a current-carrying wire, and allows you to calculate its strength at various points.
B=(μ0/4*π)*q*v*r(unit vector)/r²
Also:
B=(μ0/4*π)*q*v*sin(θ)/r²
Where;
μ0 =permeability of free space = 4πx10-7 Hm-1
B = magnetic field in Tesla
V= velocity
r= radius
Therefore:
B=(4πx10-7/4*π)*q*v*sin(θ)/r^2
B=1x10-7*q*v*sin(θ)/r^2
Using:
q=15x10-3C
v=40m/s
tan(θ)=5/2 so θ=68.2°
r²=5²+2² (Pythagoras Theorem)
B can be calculated as:
B=1x10-7*15x10-3*40*sin(68.2)/(5²+2²)
B=1.92nT
Acceleration = r w² radius r = 0.82 meter angular velocity w
4.7 = 0.82 w²
So w = 2.394 radians / sec
Time period T = time duration for completing one revolution = 2 π / w
= 2π / 2.394 = 2.624 seconds
After 1 second, the dropped ball has fallen:
s = ut + 1/2 gt^2
s = 0 + 1/2 (-10) 1^2
s = - 5 m from starting point
After 1 second, the thrown ball has risen:
s = ut + 1/2 gt^2
s = 20 (1) + 1/2 (-10) 1^2
s = 20 -5 m
s = + 15 m from starting point
The two balls meet one second after release and meet at a point 15 meters above ground.