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Neporo4naja [7]
3 years ago
11

Ions are charged particles. therefore, ions must always have and unequal number of

Chemistry
1 answer:
Kitty [74]3 years ago
6 0
Atoms in element of the periodic table
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A flashbulb of volume 2.70 mL contains O2(g) at a pressure of 2.30 atm and a temperature of 30.0 °C. How many grams of O2(g) doe
Sholpan [36]
P = 2.30 atm

Volume in liter = 2.70 mL / 1000 => 0.0027 L

Temperature in K = 30.0 + 273 => 303 K

R = 0.082 atm

molar mass O2 = 31.9988 g/mol

number of moles O2 :

P * V = n * R* T

2.30 * 0.0027 = n * 0.082 * 303

0.00621 = n * 24.846

n = 0.00621 / 24.846

n = 0.0002499 moles of O2

Mass of O2:

n = m / mm

0.0002499 = m / 31.9988

m = 0.0002499 * 31.9988

m = 0.008 g
3 0
3 years ago
36
LiRa [457]
Omg that is that ( but I do not know this
4 0
2 years ago
Read 2 more answers
How many bonds are broken in 2O2
nirvana33 [79]

Answer:

c5mvmifvidvj8dvj9r kf9,g

8 0
2 years ago
A sample of water vapor has a volume of 3.15 L, a pressure of 2.40 atm, and a temperature of 325 K. What is the new temperature,
lara31 [8.8K]

Answer:

The answer to your question is:   T2 = 235.44 °K

Explanation:

Data

V1 = 3.15 L                    V2 = 2.78 L

P1 = 2.40 atm               P2 = 1.97 atm

T1 = 325°K                    T2 = ?

Formula

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Process

            T2 = (P2V2T1) / (P1V1)

            T2 = (1.97x 2.78x 325) / (2.40 x 3.15)

            T2 = 1779.895 / 7.56

            T2 = 235.44 °K

4 0
2 years ago
which statement best describes the equation caco3 2hcl → cacl2 co2 h2o? caco3 is a reactant; it is present before the reaction o
fomenos

Answer: CaCO_3 is a reactant; it is present before the reaction occurs.

Explanation:

In a chemical reaction the chemical formulas written before the arrow are described as reactants as they react together to form products which are written after the arrow.

CaCO_3 + 2HCl \rightarrow CaCl_2 + CO_2 + H_2O

Thus CaCO_3 and HCl are reactants here whereas CO_2, CaCl_2 and H_2O are products.

7 0
3 years ago
Read 2 more answers
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